If tan 0 = ½ then what is sin 0?

What would this problems answer be ?12y=2 1\4

mafiozo [28]

Answer:

Step-by-step explanation:12y ×4 =21

48y=21

Y=0.44

Mark brainlest if correct pls

5 0

3 years ago

can anyone help me with these? I'm having a lot of trouble and I'm extremely behind... I need to catch up badly!!! i have been a

TiliK225 [7]

Answer:

Step-by-step explanation:

5 and 6 are the same, so I will do one of those and you can use the example to do the other one.

Slope-intercept form is y = mx + b. If we have 2 points and nothing else, we can use those 2 points in the slope formula to find the slope (the m value in the equation) and then plug that in with either one of the points to get the equation. The slope formula is:

$m=\frac{y_{2} -y_{1} }{x_{2}-x_{1} }$

Using our points in question 5: (2, 4) (5, 4)

$m=\frac{4-4}{5-2} =\frac{0}{3}=0$ So m = 0. Now pick a point and use it in the equation along with the m value to solve for b. I will use (2, 4):

4 = 0(2)+b and

4 = 0 + b so

b = 4.

Now we have m = 0 and b = 4 so we fill in the equation with that info:

y = 0x + 4 or simplifying,

y = 4

For question 7 they want the line parallel to y = 3x + 6 that goes through (-10, 2.5). For a line to be parallel to another line, their slopes have to be identical. The slope in y = 3x + 6 is 3. So the slope of the "new" line is going to be 3 as well. Now we will use that slope and the given point to solve for b, just like in #5:

2.5 = 3(-10) + b and

2.5 = -30 + b so

b = 32.5

Now we will fill in:

y = 3x + 32.5

For question 8 they want the line perpendicular to y = -4x - 2 that goes through (-16, -11). For a line to be perpendicular to another line, their slopes have to be opposite reciprocals. Opposite meaning the sign is opposite (positive becomes negative and negative becomes positive), and reciprocal meaning the fraction is flipped upside down. The slope in our line is -4. That means that the perpendicular slope is positive 1/4. Using that along with our point, we will again solve for b:

$-11=\frac{1}{4}(-16)+b$ which simplifies to

-11 = -4 + b so

b = -7

Now we fill in:

$y=\frac{1}{4}x-7$

For question 8, in order to find the line parallel to the given line, you need to know the slope. In the form it is currently in, we do not know the slope. We need to put it into slope-intercept form to find the slope, then we will proceeed as above. If

x + 4y = 6, then

4y = -x + 6 and, dividing by 4,

$y=-\frac{1}{4}x+\frac{3}{2}$

(The 3/2 is reduced from 6/4)

Now we can see the slope is -1/4. We use that along with the point (-8, 5) to solve for b:

$5=(-\frac{1}{4})(-8)+b$ which simplifies to

5 = 2 + b so

b = 3

Now we fill in, keeping in mind that lines are parallel when they have the exact same slope:

$y=-\frac{1}{4}x+3$

6 0

3 years ago

Find x please so difficult

Colt1911 [192]

Answer:

120 degrees

Step-by-step explanation:

Attached is a screenshot.

y = 180 - 50 - 70 = 60.

x + y = 180, so x = 120

Remember to try to use parallel lines when you can

The second uses the same method, just the opposite side.

4 0

2 years ago

Find the area bounded by the graphs of the indicated equations over the given interval.

NeX [460]

Answer:

48

Step-by-step explanation:

$y = 0$

is basically the horizontal axis.

First, find the integral of x^2-25.

Remember that

integral of a constant is that constant times x.

Also that

to take the integral of a power function, add 1 to the degree and divide by that same degree.

$y = {x}^{2} - 25$

We then get

$\frac{ {x}^{3} }{3} - 25x$

Evaluate at -3

$\frac{ - 3 {}^{3} }{3} - 25( - 3)$

$- 27 + 75 = 48$

Then we evaluate at 0

$\frac{0 {}^{3} }{3} - 25(0) = 0$

Next, we subtract the the answer then we get

$48 - 0 = 48$

8 0

2 years ago

graph the parabola y equals negative x squared + 3 to graph a parabola plot the vertex and four additional points two on each si

Nataliya [291]

You don't have the graph icon here, so we'll have to graph this parabola without it.

Your parabola is y = -x^2 + 3., which resembles y = a(x-h)^2 + k. We can tell immediately that this parabola opens down and that the vertex is (0,3).

Plot (0,3). Besides being the vertex, this point is also the max. of the function.

Now calculate four more points. Choose four arbitrary x-values, such as {-2, 1, 4, 5} and find the y value for each one. Plot the resulting four points. Draw a smooth curve thru them, remembering (again) that the vertex is at (0,3) and that the parabola opens down.

6 0

2 years ago