Answer:below hopes it helps the link should help aswell
Step-by-step explanation:
https://mathsolver.microsoft.com/en/solve-problem/%60frac%7B%2010%20%7B%20q%20%20%7D%5E%7B%205%20%20%7D%20%20%20%7B%20w%20%20%7D%5E%7B%207%20%20%7D%20%20%20%20%7D%7B%202%20%7B%20w%20%20%7D%5E%7B%203%20%20%7D%20%20%20%20%7D%20%20%20%60frac%7B%204%20%7B%20%60left(%20%7B%20q%20%20%7D%5E%7B%206%20%20%7D%20%20%20%60right)%20%7D%5E%7B%202%20%20%7D%20%20%20%20%7D%7B%20%20%7B%20w%20%20%7D%5E%7B%20-5%20%20%7D%20%20%20%20%7D
If you meant to write y=23x-4 then none of the lines are perpendicular.
I suspect you intended y=2/3x-4, then line D, y=-3/2x-4 is perpendicular.
For any line y=mx+b, you have to "invert" m to get a perpendicular line. Inverting in this case means: flip numerator and denominator and add a minus sign.
So 2/3 becomes -3/2, hence answer D.
The 'inverted' m is called the opposite reciprocal. That's your word of the day.
The point where the two diagonals meet is also the midpoint of both diagonals.
This means that AE = EC . Since we have the value for both segments, we have
Since AC = AE + EC, we have
So area=1/2 base times height
50=1/2 base times height
multiply both sides by 2
100=base times height
base=4height
100=4height times height
100=4height^2
divide 4
25=height^2
squarer root
5=height
subisute
base=4(5)
base=20
height=5
Answer:
wowowowowowow cool
Step-by-step explanation:
the answer is easy nobody cares :)
