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oksian1 [2.3K]
3 years ago
15

Mila spends a winter day recording the temperature once every three hours for science class. At 9 am, the temperature was -1.6°F

. Between 9am and noon, the temperature rose 6.6°F. Between noon and 3pm, the temperature increased by 2.8°F. Between 3pm and 6pm, the temperature went down 10.5°F. What was the temperature at 6pm?
Mathematics
1 answer:
liubo4ka [24]3 years ago
6 0

The Black Valley in Kerry, which only saw the arrival of electricity in the 1970s, is to get high-speed satellite-delivered internet this year in a pilot project funded by technology billionaire Elon Musk.Musk, founder of SpaceX and electric carmaker Tesla

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a survey asked 50 students if they play an instrument and if they are in band. 25 students play an instrument 20 are in a band a
frutty [35]
I would go with d .... If not it would be c...


Really hope I help but I would choose d
5 0
4 years ago
Read 2 more answers
Evaluate the expression when y = -2 and z = -5. Show your work
katen-ka-za [31]
10(-2)^2/-5
The solution to this would equal to -8

:)  You are using substitution which is putting the number as the variable or the letter.

3 0
3 years ago
Dwayne earns $11.45 per hour. Last week he worked for
Rufina [12.5K]
38 1/4 hours* ($11.45/ 1 hour)= $437.96

Dwayne earned $437.96 last week~
5 0
4 years ago
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Use the definition of the derivative as a limit to find the <br> derivative f′ where f(x)= √ x+2.
MA_775_DIABLO [31]

Step-by-step explanation:

If the equation is

\sqrt{x + 2}

Then, here is the answer.

The definition of a derivative is

\frac{f(x + h) - f(x)}{h}

Also note that we want h to be a small, negligible value so we let h be a value that is infinitesimal small.

So we get

\frac{ \sqrt{x + h + 2} -  \sqrt{x + 2}  }{h}

Multiply both equations by the conjugate.

\frac{ \sqrt{x + h + 2} -  \sqrt{x + 2}  }{h}  \times  \frac{ \sqrt{x + h + 2} +  \sqrt{x + 2}  }{ \sqrt{x + h + 2} +  \sqrt{x + 2}  }  =  \frac{x + h + 2 - (x + 2)}{h \sqrt{x +  h + 2} +  \sqrt{x + 2}  }

\frac{h}{h \sqrt{x + h + 2}  +  \sqrt{x + 2} }

\frac{1}{ \sqrt{x + h + 2}  +  \sqrt{x + 2} }

Since h is very small, get rid of h.

\frac{1}{ \sqrt{x + 2} +  \sqrt{x + 2}  }

\frac{1}{2 \sqrt{x + 2} }

So the derivative of

\frac{d}{dx} ( \sqrt{x + 2} ) =  \frac{1}{2 \sqrt{x + 2} }

Part 2: If your function is

\sqrt{x}  + 2

Then we get

\frac{ \sqrt{x + h} + 2 - ( \sqrt{x}  + 2) }{h}

\frac{ \sqrt{x + h}  -  \sqrt{x} }{h}

\frac{x + h - x}{h( \sqrt{x + h}   +  \sqrt{x}) }

\frac{h}{h( \sqrt{x + h} +  \sqrt{x} ) }

\frac{1}{ \sqrt{x + h} +  \sqrt{x}  }

\frac{1}{2 \sqrt{x} }

So

\frac{d}{dx} (  \sqrt{x}  + 2) =  \frac{1}{2 \sqrt{x} }

3 0
3 years ago
Using division, what is the quotient (2x3 − 2x − 12) ÷ (x − 2)?
topjm [15]

Answer:

2x^2 + 4x + 6

Step-by-step explanation:

First, we need to write the polynomial in descending order, since we have a missing term (x^2) we need to fill with zero:

2X^3+0x^2-2x-12

Then, grab the term with the highest  power from the polynomial and divide it by the term with highest power from the polynomial located at the other side of the division symbol (this polynomial would be x-2)

The result (2x^3 / x) = 2x^2

This term will be part of the solution, and will be use to start the process of division.

This process start with the previous obtained term (2x^2), which will be multiplied by the polynomial from the other side of the division symbol (x-2).

The result another is another polynomial

This new polynomial will be multiply by negative 1

The new polynomial is then added to the poly (2X^3+0x^2-2x-12)

The result will constitute a new poly, that will be use as the remaining of the division.

Since, our remaining differs from zero, and we still have member to simplify, we repeat the step 1 using the remaining as the new poly that needs to be divided by (x-2).

The attached picture explains the whole procedure.

3 0
4 years ago
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