7. (07.03)
1 answer:
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Answer:
a = 94
b = -66√3
Step-by-step explanation:
Given z =
[(a + b)³ = a³ + b³ + 3a²b + 3ab²]
= [1 + 3i² + 3i√3 + 9i²]²
= [1 - 3 + 3i√3 - 9]²
= [-11 + 3i√3]²
= (11)² -2(3i√3)(11) + (3i√3)²
= 121 - 66i√3 + 27i²
= 121 - 66i√3 - 27
= (94 - 66i√3)
Comparing it with (a + bi),
a = 94 and b = -66√3