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amm1812
3 years ago
6

PLEASE HELP ME IM STUCK

Mathematics
2 answers:
Tanya [424]3 years ago
8 0

Answer:

B

Step-by-step explanation:

(5x^{2} + 7) - (3x - 2)\\5x^{2} + 7 - 3x - (-2)\\5x^{2} + 7 - 3x + 2\\ B - 5x^{2} - 3x + 9\\

Tems11 [23]3 years ago
3 0

Answer:

5x^2  -3x  +9

Step-by-step explanation:

To subtract, line up the common terms.  I add a 0 term to keep the terms in line.

5x^2  + 0x  +7

- (0x^2 +3x-  2 )

------------------------


Distribute the negative sign.

5x^2  + 0x  +7

- 0x^2 -3x  + 2

------------------------

5x^2  -3x  +9

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5 0
3 years ago
Nitric acid (specific gravity 1.42) costs $51.95 per liter. A student spills 5.112 kg of nitric acid in the laboratory, what is
Leno4ka [110]

Answer:

The cost of wasted nitric acid is $187.02

Step-by-step explanation:

Since it is given that specific gravity of Nitric Acid is 1.42 Thus the density of nitric acid is

\rho _{acid}=S.G\times \rho _{water}\\\\\\\rho_{acid}=1.42\times 1\frac{g}{cm^3}\\\\\rho_{acid}=1.42g/cm^3

Now from the basic relation of mass volume and density we have

\rho =\frac{Mass}{Volume}\\\\\therefore Volume=\frac{Mass}{\rho }

Since the mass of the nitric acid is given to be 5.112 kg = 5112 grams

Thus the volume of nitric acid is

Volume=\frac{5112}{1.42}=3600cm^3

Now we know that 1000 cubic centimeters euals 1 litrer

Thus the calculated volume in liters is

V_{liters}=\frac{3600}{1000}=3.6Liters

Thus the cost of acid spilled  equals

Cost=3.6\times 51.95=187.02

5 0
3 years ago
How to do this problem
ANTONII [103]
First move the decimal by one and add a 0 and then a decimal after the 0.
then divide from there
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