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kherson [118]
3 years ago
15

Help please. r/5 - 6 = -1 A) r = 1 B) r = 5 C) r = 10 D) r = 25

Mathematics
1 answer:
statuscvo [17]3 years ago
5 0
Hello :),

\frac{r}{5}-6=-1 \\    \\ \frac{r}{5} =-1+6=5 \\  \\  r=5*5=25.
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Using π = 3.14, find the area of a circle with a radius of 16.
timama [110]
29 because the original answer would have been 28.26
7 0
3 years ago
A school snack bar sells a mix of granola and raisins. The mix includes 2 pounds of granola for every 3 pounds of raisins. How m
kifflom [539]
The easiest way to solve a problem like this is to cross multiply and solve 

The problem gives us a ratio 
2 pounds of granola = 3 pounds of raisins 
which makes a ratio of \frac{2}{3}
The other ratio is 
? pounds of granola = 24 pounds of raisins
which makes a ratio of \frac{x}{24}

To solve, set them equal to each other ...
\frac{2}{3} =  \frac{x}{24}

Now we must cross multiply...
To cross multiply, we multiply 2 and 24 
and we multiply 3 and x 
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3x = 48 
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x = \frac{48}{3}

x = 16
You'll need 16 pounds of granola 
5 0
3 years ago
Find f(-3) for f(x) = 4(2)^x.<br> ОА. 1/8<br> O B. -32<br> O C. -24<br> OD. 1/2
Ipatiy [6.2K]

Answer:

D

Step-by-step explanation:

using the rule of exponents

a^{-m} = \frac{1}{a^{m} }

substitute x = - 3 into f(x)

f(- 3) = 4((2)^{-3} = 4 × \frac{1}{2^{3} } = 4 × \frac{1}{8} = \frac{1}{2}

5 0
2 years ago
Here are 15 cards, numbered 1 through 15. if you pick a card, what is the probability that you choose an odd number or a two?
kondor19780726 [428]
9/15. There are 15 cards and 8 of them are odd and 1 is a 2. 
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3 years ago
8x2 − 5 + 7x4 − 9x − x5
Veseljchak [2.6K]

Answer:

=-\left(x-1\right)\left(x^4-6x^3-6x^2-14x-5\right)

Step-by-step explanation:

Factor out comon Term -1

=-\left(x^5-7x^4-8x^2+9x+5\right)

Factor x^5-7x^4-8x^2+9x+5:\quad \left(x-1\right)\left(x^4-6x^3-6x^2-14x-5\right)

x^5-7x^4-8x^2+9x+5

Use the rational root theorem

a_0=5,\:\quad a_n=1

The dividers of a_{0}: 1, 5, The dividers of a_n: 1

Therefore, check the following rational numbers: ±\frac{1,\:5}{1}

\frac{1}{1} is a root of the expression, so factor out x-1

=\left(x-1\right)\frac{x^5-7x^4-8x^2+9x+5}{x-1}

\frac{x^5-7x^4-8x^2+9x+5}{x-1}=x^4-6x^3-6x^2-14x-5

=x^4-6x^3-6x^2-14x-5

=-\left(x-1\right)\left(x^4-6x^3-6x^2-14x-5\right)

8 0
3 years ago
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