Answer:
4
Step-by-step explanation:
hbjhb
<span>Diviseur de 63 et 67</span>
<span>
</span>
<span>0.94029850746</span>
We have: x × 
÷ 
= x × × 
= x × 
= x ÷ 
ANSWER: E. 4/5
Ok done. Thank to me :>
1. 0.2,0.4,0.54,0.61
2.0.02,0.11,0.3,0.45
3.1.02,1.24,1.33,1.7
4.1.01,1.06,1.2,1.42
5.0.87,0.9,0.98,1.23
6.0.06,0.5,1.4,1.23
7.0.003,0.031,0.033.0.03
8.0.002.0.022.0.02.0.2
If you apply the or both
Only 1 of the students would need to know the "or both", therefore maximizing the remaining amount of students you can put in.
Gerald, let's call him, knows French AND German, so there's only one less student that knows french and german. Gerald is 1 student.
MAXIMUM:
There are now 14 monolinguistic French speakers and 16 monolinguistic German's, 30 students + Gerald=31.
Minimum:
As a bonus, the minimum is 15 students knowing french AND German and only 2 monolinguistic German speakers, so 17.
