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laila [671]
3 years ago
13

What is the area of the shaded region??

Mathematics
2 answers:
NikAS [45]3 years ago
6 0
The answer is 48 units squared

Juliette [100K]3 years ago
5 0
Width of shaded part:

6^2+2^2=w^2
36+4=w^2
40=w^2
w= sqare root 40
w= 6.32455532



length of shaded part:

12^2+4^2=l^2
144+16=l^2
160=l^2
l=square root of 160
l=12.6491106407

area=12.6491106407*6.32455532
=79.9999999959which is 80, because those decimals are endless, if you multiply 12.6491106407*6.32455532, answer wouldn't be accurate, so you should round up to 80. If you use another way to solve the q, which is calculate the bigger rectangle and then subtract the area of the triangles, you will get 80 as your answer.
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Can someone help me please? Thank you very much! Correct answer only ​
lbvjy [14]

Answer:

X⁰ = 240°

y = 8 cm

Step-by-step explanation:

explanation provided in image shown and the proving of each angle properties are labelled with brackets(meaning they are legitimate so dont worry )

happy learning !

7 0
3 years ago
Alfred is building a slide for a new park. He wants the height of the slide to be 8 feet, and he wants the horizontal distance a
oksano4ka [1.4K]

Answer:

5ft

Step-by-step explanation:

8/10=0.8

4/0.8=5

8 0
2 years ago
To decrease an amount by 8 percent, what single multiplier would you use?
Alchen [17]
That's far more problems than I usually accept in a single question, but since you're new and obviously a beginner, I'll try to help. 

<span>To Increase an amount by 7% what single multiplier would you use </span>
<span>We want 7% more than 100% of the amount, so the multiplier is </span>
<span>(100% + 7%) = 107% = 1.07 </span>
<span>[Remember that "percent" means "per hundred," so we divide a percentage by 100 to get the numerical equivalent.] </span>

<span>To Decrease an amount by 7% what single multiplier would you use </span>
<span>We want 7% less than 100% this time, so the multiplier is </span>
<span>(100% - 7%) = 93% = 0.93 </span>

<span>5 ÷ 0.1 </span>
<span>= 50 </span>

<span>(To One Decimal Place) (0.3 x 2.8)Squared </span>
<span>[Notation: around here we usually write "squared" as ^2, where the ^ is an exponentiation sign.] </span>
<span>(0.3 x 2.8)^2 = 0.84^2 = 0.7056 </span>
<span>which is 0.7 when rounded to one decimal place. </span>

<span>6.38 + 4.52 ÷ 4.71 +9.53 </span>
<span>= 6.38 + (4.52 ÷ 4.71) + 9.53 [assuming operations in the usual order] </span>
<span>= about 6.38 + 0.96 + 9.53 </span>
<span>= 16.87 </span>

<span>Expand and Simplify </span>
<span>(x + 2)(x + 3) </span>
<span>= x^2 + 2x + 3x + 6 </span>
<span>= x^2 + 5x + 6 </span>

<span>Expand and Simplify </span>
<span>(x + 2)(x - 3) </span>
<span>= x^2 + 2x - 3x - 6 </span>
<span>= x^2 - x - 6 </span>

<span>x + 1 < 5 </span>
<span>x < 4 [subtracting 1 from both sides] </span>

<span>Make n the subject of the formula.... M=3n </span>
<span>3n = M </span>
<span>n = M/3</span>
5 0
3 years ago
Please answer the following questions​
Vlada [557]

Step-by-step explanation:

sorry I can only explain as there are no labels to each diagram

The first diagram is single and can solved using triangular formular given as 1/2 ×base × height

A = 1/2 × 5 × 12

A = 30cm^2..

as for the second one...it consist of 2 diagrams which will be solved separately before adding ...it can simply be done using Pythagoras theorem..

To get the smaller part ...out tita is 45degrees while our adjacent is 4 and opposite is x we are to find x which is the height...

using SOH CAH TOA...

WE HAVE TAN45= opp/adj

Tan45= x/ 4

Tan 45 =1 ...so

1 = x/ 4

and x= 4 ...

so...having our height as 4 and base as 4 ..

Area of smaller triangle become 1/2 × 4 × 4

A = 8cm^2 ...

......SOLVING FOR THE SECOND DIAGRAM ..

WE HAVE the height as ( dotted spot + undotted spot ) = 4 + 4 = 8cm

and our base can be gotten from

Tan45 = opp / adj

1 = 8/x ..

x = 8cm ....so the base is 8 and the height is 8

..

The Area becomes 1/2 × 8×8 = 32cm ...

Total area becomes 32cm + 8cm = 40cm^2

5 0
3 years ago
When dealing with the number of occurrences of an event over a specified interval of time or space and when the occurrence or no
jeyben [28]

Answer:

POISSON DISTRIBUTION

Step-by-step explanation:

When dealing with the number of occurrences of an event over a specified interval of time or space, the poisson distribution is often useful.

Poisson distribution is applicable if:

The probability of the occurrence of the event is the same for any two intervals of equal length.

The occurrence or nonoccurrence of the event in any interval is independent of the occurrence or nonoccurrence in any other interval.

The probability that two or more events will occur in an interval approaches zero as the interval becomes smaller.

Therefore, the appropriate probability distribution is POISSON PROBABILITY DISTRIBUTION.

7 0
3 years ago
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