Can some PLEASE help me this is my 3rd time asking the same question

Pls answer me this all question

Scorpion4ik [409]

Answer:

a. $5 \frac{21}{40}$

b. $\frac{1}{42}$

Step-by-step explanation:

$a. \: 12 \frac{2}{5} - 6 \frac{7}{8}$

$\frac{62}{5} - \frac{55}{8}$

$\frac{62}{8} \times \frac{8}{8} - \frac{55}{8} \times \frac{5}{5}$

$\frac{62 \times 8 - 55 \times 5}{40}$

$\frac{221}{40}$

$5 \frac{21}{40}$

$b. \: \frac{3}{14} - \frac{4}{21}$

$\frac{3}{14} \times \frac{3}{3} - \frac{4}{21} \times \frac{2}{2}$

$\frac{3 \times 3}{42} - \frac{4 \times 2}{42}$

$\frac{1}{42}$

Hope it is helpful....

5 0

3 years ago

Read 2 more answers

Cancel the common factor of the numerator and the denominator and write specified expression

lisabon 2012 [21]

Step-by-step explanation:

Hello,

I hope you mean to cancel the common factor that exists in numerator and denominator,right.

so, Let's look for the common factor, 

here, the expression is, 

=4(x-2)/ (x+5)(x-2)

so, here we find the common factor is (x-2)

now, we have to cancel it. And after cancelling we get,

=4/(x+5)

Note:{ we cancel the common factor if the common factors are in multiply form.}

Hope it helps 

3 0

3 years ago

in a recent semester at a local university 520 students enrolled in both general chemistry and calculus 1. Of these students 88

IceJOKER [234]

Let Ch and C denote the events of a student receiving an A in chemistry or calculus, respectively. We're given that

P(Ch) = 88/520

P(C) = 76/520

P(Ch and C) = 31/520

and we want to find P(Ch or C).

Using the inclusion/exclusion principle, we have

P(Ch or C) = P(Ch) + P(C) - P(Ch and C)

P(Ch or C) = 88/520 + 76/520 - 31/520

P(Ch or C) = 133/520

6 0

3 years ago

Sean answers 4/5 of the questions on a test correctly. If there are 100 questions, how many did he not answer correctly?

DanielleElmas [232]

He would have answered 20 incorrectly.

3 0

3 years ago

Read 2 more answers

Find the average range. Round the mean and the average range to the nearest tenth. (Show all your work on scratch paper, then en

NISA [10]

3, 12, 15, 25, 30, 40The range is the difference between the greatest and smallest values:
range = 40 - 3 = 37

Thee average is the sum of elements divided by the number of elements:
average = (3 + 12 + 15 + 25 + 30 + 40)/6
average = 125/6 = 20.83

4 0

3 years ago