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3 years ago

Describe a real-world situation that is a model by multiplying two fractions or mixed numbers

1 answer:

4 0

Construction.

When construction workers need measurements that are fractions they need to be able to multiply/add/subtract/divide all of those different fractions and mixed numbers.

I hope I was able to help. Best of luck.

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A manufacturer of paper coffee cups would like to estimate the proportion of cups that are defective (tears, broken seems, etc.)

Maksim231197 [3]

Answer:

The 95% confidence interval is $0.0503 < p < 0.1297$

The sample proportion is $\r p = 0.09$

The critical value is $Z_{\frac{\alpha }{2} } = 1.96$

The standard error is $SE =0.020$

Step-by-step explanation:

From the question we are told that

The sample size is n = 200

The number of defective is k = 18

The null hypothesis is $H_o : p = 0.08$

The alternative hypothesis is $H_a : p > 0.08$

Generally the sample proportion is mathematically evaluated as

$\r p = \frac{18}{200}$

$\r p = 0.09$

Given that the confidence level is 95% then the level of significance is mathematically evaluated as

$\alpha = 100 - 95$

$\alpha = 5\%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{ \alpha }{2}$ from the normal distribution table, the value is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the standard of error is mathematically represented as

$SE = \sqrt{\frac{\r p (1 - \r p)}{n} }$

substituting values

$SE = \sqrt{\frac{0.09 (1 - 0.09)}{200} }$

$SE =0.020$

The margin of error is

$E = Z_{\frac{ \alpha }{2} } * SE$

=> $E = 1.96 * 0.020$

=> $E = 0.0397$

The 95% confidence interval is mathematically represented as

$\r p - E < \mu < p < \r p + E$

=> $0.09 - 0.0397 < \mu < p < 0.09 + 0.0397$

=> $0.0503 < p < 0.1297$

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3 years ago

Antonio and Candice had a race. Their distances past a particular landmark as the race progressed can be represented by linear f

Luda [366]

I got the answer Antonio had a head start of 3 meters.

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Will give brainiest Find the equation of the straight line parallel to the y-axis and passes through the point (-2, 3). _____

IrinaVladis [17]

Answer:

Step-by-step explanation:

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2 years ago

How many real number solutions are there to the equation 0=-3x^2 + x -4

natta225 [31]

We have that
the equation
y=-3x² + x -4
the real number solutions are the points x intercept of the graph
are the points when y=0

using a graph tool
see the attached figure

the graph has no point of intersection with the x axis
therefore

the answer is
there are zero real numbers solutions

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Andrews [41]

3 per hour for each barber

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