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3 years ago

7

Complete the input-output table for the linear function y = 3x. a= b= c=

1 answer:

Helen [10]3 years ago

4 0

Answer:

The answer would be A. 1 1/5

48/40 = 1 8/40

1 8/40 Simplify to 1 1/5

Hope this helps!

Step-by-step explanation:

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Convert 750ft to metre

Angelina_Jolie [31]

One meter is composed of approximately 3.28 feet. To convert a certain measure in feet to meter, divide the number by 3.28. From the given above, using dimensional analysis and the conversion factor,

(750 ft) x (1 m/ 3.28 ft) = 228.66 m

Thus, 750 ft is approximately 228.66 in meters.

6 0

3 years ago

What should be the paper weight

nata0808 [166]

Answer:

6.25 cm

Step-by-step explanation:

$\rho=\dfrac{m}{V} \\\\V_{\text{pyramid}}= A_{\text{base}}\cdot h \cdot \dfrac{1}{3} \\\\1.6=\dfrac{400}{V} \\\\V=120 \cdot h \cdot \dfrac{1}{3} \\\\1.6=\dfrac{400}{40h} \\\\1.6=\dfrac{10}{h} \\\\1.6h=10 \\\\h=\dfrac{10}{1.6}=6.25\text{ cm}$

Hope this helps!

8 0

3 years ago

Read 2 more answers

Julie had $10.00 in her savings account when she earned $23.50 doing errands for her next-door neighbor. Julie used her savings

AleksandrR [38]

Answer:

<h2>$5.75</h2>

Step-by-step explanation:

Step one:

given data

initial balance= $10

she earned extra $23.50 doing errands

hence her balance will be

=10+23.5

=$33.5

Step two:

Required is her balance

we are told that she bought shoes for $27.75

hence her balance will be

=33.5-27.75

=$5.75

8 0

3 years ago

Given: ABC is a right triangle with right angle C. AB = 18 centimeters and m∠A = 22 degrees.

Vika [28.1K]

6.743=BC
this is the answer

8 0

3 years ago

Read 2 more answers

Suppose a simple random sample of size nequals36 is obtained from a population with mu equals 74 and sigma equals 6. (a) Descri

OlgaM077 [116]

Part a)

The simple random sample of size n=36 is obtained from a population with

$\mu = 74$

and

$\sigma = 6$

The sampling distribution of the sample means has a mean that is equal to mean of the population the sample has been drawn from.

Therefore the sampling distribution has a mean of

$\mu = 74$

The standard error of the means becomes the standard deviation of the sampling distribution.

$\sigma_ { \bar X } = \frac{ \sigma}{ \sqrt{n} } \\ \sigma_ { \bar X } = \frac{ 6}{ \sqrt{36} } = 1$

Part b) We want to find

$P(\bar X \:>\:75.9)$

We need to convert to z-score.

$P(\bar X \:>\:75.9) = P(z \:>\: \frac{75.9 - 74}{1} ) \\ = P(z \:>\: \frac{75.9 - 74}{1} ) \\ = P(z \:>\: 1.9) \\ = 0.0287$

Part c)

We want to find

$P(\bar X \: < \:71.95)$

We convert to z-score and use the normal distribution table to find the corresponding area.

$P(\bar X \: < \:71.95) = P(z \: < \: \frac{71.9 5- 74}{1} ) \\ = P(z \: < \: \frac{71.9 5- 74}{1} ) \\ = P(z \: < \: - 2.05) \\ = 0.0202$

Part d)

We want to find :

$P(73\:$

We convert to z-scores and again use the standard normal distribution table.

$P( \frac{73 - 74}{1} \:< \: z$

5 0

3 years ago