Water has a molar mass of 18.015 g/mol . This means that one mole of water molecules has a mass of 18.015 g . So, to sum this up, 6.022⋅1023 molecules<span> of water will amount to 1 mole of water, which in turn will have a mass of 18.015 g . 2.7144moles H2O ⋅</span>6.022<span>⋅1023molec.1mole H2O =1.635⋅1024molec.</span>
im not understanding the question, but if its a solid then the reactants are precipitate
Answer:
0.367M
Explanation:
Molarity refers to the molar concentration of a solution. It can be calculated using the formula below:
Molarity = n/V
Where;
n = number of moles (mol)
V = volume (L)
According to the given information in this question;
n = 0.55 mole
V = 1.50 L
Molarity = 0.55/1.50
Molarity = 0.367M
The mass of titanium is = 47,867 g/1mol
Applying the rule of avrogado
1mol _______ 6,023 × 10^(23) at
0,075mol ___ x
X . 1mol = 0,075mol . 6,023 . 10^(23)at
X = 0,075 . 6,023 . 10^(23) at
X = 4,51 . 10^(22) atoms
Hope this helps
Answer:
94.325 g
Explanation:
We'll begin by converting 350 mL to L. This can be obtained as follow:
1000 mL = 1 L
Therefore,
350 mL = 350 mL × 1 L /1000 mL
350 mL = 0.35 L
Next, we shall determine the number of mole of KC₂H₃O₂ in the solution. This can be obtained as follow:
Volume = 0.35 L
Molarity of KC₂H₃O₂ = 2.75 M
Mole of KC₂H₃O₂ =?
Molarity = mole /Volume
2.75 = Mole of KC₂H₃O₂ / 0.35
Cross multiply
Mole of KC₂H₃O₂ = 2.75 × 0.35
Mole of KC₂H₃O₂ = 0.9625 mole
Finally, we shall determine the mass of KC₂H₃O₂ needed to prepare the solution. This can be obtained as illustrated below:
Mole of KC₂H₃O₂ = 0.9625 mole
Molar mass of KC₂H₃O₂ = 39 + (12×2) +(3×1) + (16×2)
= 39 + 24 + 3 + 32
= 98 g/mol
Mass of KC₂H₃O₂ =?
Mass = mole × molar mass
Mass of KC₂H₃O₂ = 0.9625 × 98
Mass of KC₂H₃O₂ = 94.325 g
Thus, the mass of KC₂H₃O₂ needed to prepare the solution is 94.325 g
