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4 years ago

Why is the solubility of a neutral organic compound unaltered by exposure to aqueous acid or base?

1 answer:

jeka944 years ago

6 0

Adding an acid or base adds a greater charge in the water, which makes slightly charged compounds dissolve better than they would have on their own. However, if the substance is neutral, it is not affected by the presence of any charge and cannot be made to dissolve by adding acid or base.

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Based on the chart below, which of the tests measured physical properties?

sp2606 [1]

Density and phase are both physical properties

7 0

3 years ago

Part a how many carbon atoms are in a 2-carat pure diamond that has a mass of 0.40 g . express your answer using two significant

shutvik [7]

We have to calculate the number of carbon atoms present in 2-carat pure diamond.

The number of carbon atoms present in 2-carat pure diamond is: 0.19 X 10²³ number of carbon atom.

Diamond is one allotrope of carbon. Atomic mass of carbon is 12.

Mass of one mole carbon atom is 12 g. One mole carbon contains Avogadro's number i.e, 6.023 X 10²³ number of atoms.

0.40 g diamond contains 0.40/12 moles= 0.033 moles of carbon atom.

So, number of carbon atoms present in 0.40 g diamond (i.e, 0.033 mole diamond) is 0.033 X 6.023 X 10²³= 1.98 X 10²²=0.19 X 10²³ .

Therefore, 0.19 X 10²³ number of carbon atoms are in a 2-carat pure diamond that has a mass of 0.40 g

3 0

4 years ago

Ag(s)+CN−(aq)+O2(g)→Ag(CN)−2(aq) Express your answer as a chemical equation. Identify all of the phases in your answer. Express

Lerok [7]

Answer : The balanced redox reaction will be,

$4Ag(s)+8CN^-(aq)+O_2(g)+4H^+(aq)\rightarrow 4Ag(CN)_2^-(aq)+2H_2O(l)$

Explanation :

The given chemical equation is,

$Ag(s)+CN^-(aq)+O_2(g)\rightarrow Ag(CN)_2^-(aq)$

In the half reaction method, the number of atoms in each half reaction and number of electrons must be balanced.

The half reactions in the acidic medium are :

Reduction : $O_2(g)+4H^+(aq)+4e^-\rightarrow 2H_2O(l)$ ......(1)

Oxidation : $Ag(s)+2CN^-(aq)\rightarrow Ag(CN)_2^-(aq)+1e^-$ .......(2)

Now multiply the equation (2) by 4 and then added both equation, we get the balanced redox reaction.

Thus, the balanced redox reaction will be,

$4Ag(s)+8CN^-(aq)+O_2(g)+4H^+(aq)\rightarrow 4Ag(CN)_2^-(aq)+2H_2O(l)$

7 0

4 years ago

A solution is prepared by mixing 0.0300 mol CH2Cl2 and 0.0500 mol CH2Br2 at 25 degrees C. Assuming the solution is ideal, calcul

Vinil7 [7]

Answer:

CH2Cl2 mole fraction = 0.833

CH2Br2 mole fraction = 0.167

Explanation:

Step 1: Data given

Number of moles CH2Cl2 = 0.0300 moles

Number of moles CH2Br2 = 0.0500 moles

Temperature = 25 °C

Vapor pressure of pure CH2Cl2 = 133 torr

Vapor pressure of pure CH2Br2 = 11.4 torr

Step 2: Calculate mol fraction in solution

Mol fraction CH2Cl2 = 0.0300 moles / (0.0300 + 0.0700)

Mol fraction CH2Cl2 = 0.300

Mol fraction CH2Br2 = 0.0700 moles / (0.0300 + 0.0700)

Mol fraction CH2Br2 = 0.700

Step 3: Calculate partial pressure

Partial pressure CH2Cl2 = 133 torr * 0.300 = 39.9 torr

Partial pressure CH2Br = 11.4 torr * 0.700 =7.98 torr

Step 4: Calculate the total pressure

total pressure = 39.9 + 7.98 = 47.88 torr

Step 5: Calculate mol fraction

partial pressure / total pressure = mole fraction

CH2Cl2 mole fraction = 39.9 / 47.88 = 0.833

CH2Br2 mole fraction = 7.98 / 47.88 = 0.167

3 0

3 years ago

Non example of eukaryote cell

Rom4ik [11]

Bacteria are the only type of cells that are not eukaryotic.

8 0

4 years ago