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sattari [20]
4 years ago
15

Why is the solubility of a neutral organic compound unaltered by exposure to aqueous acid or base?

Chemistry
1 answer:
jeka944 years ago
6 0
Adding an acid or base adds a greater charge in the water, which makes slightly charged compounds dissolve better than they would have on their own. However, if the substance is neutral, it is not affected by the presence of any charge and cannot be made to dissolve by adding acid or base.
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Structural formula for:<br>5 - methyl hept - 3 - enal​
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Answer:

draw the carbon chain is containing 6 carbon then attach the aldehyde group with edge carbon in chain then put the put double bond at 3 no. carbon

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3 years ago
PLEASE HELP!!!!! Noble gases are often described as being very stable. Give two points to explain what this means.
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Answer:

Noble Gases are very stable because...

1) Noble Gases have a full octet

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Explanation:

This means that is has 8 valence electrons so it won't need any more, so it is less likely to react with other substances.

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3 years ago
Water boils at 100°C at sea level. If the water in this experiment did not boil at 100°C, what could be the reason?
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Why all goals cannot be met in economics?
muminat
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4 0
3 years ago
In a coffee-cup calorimeter, 1 mol NaOH and 1 mol HBr initially at 22.5 oC (Celsius) are mixed in 100g of water to yield the fol
zavuch27 [327]

Answer:

ΔH = -55.92 kJ

Explanation:

<u>Step 1:</u> Data given

1 mol NaOH and 1 mol HBr initially at 22.5 °C are mixed in 100g of water

After mixing the temperature rises to 83 °C

Specific heat of the solution = 4.184 J/g °C

Molar mass of NaOH = 40 G/mol

Molar mass of HBr = 80.9 g/mol

<u>Step 2: </u>The balanced equation

NaOH + HBr → Na+(aq) + Br-(aq) + H2O(l)

<u>Step 3:</u> mass of NaOH

Mass = moles * Molar mass

Mass NaOH = 1 * 40 g/mol

Mass NaOH = 40 grams

Step 4: Mass of HBr

Mass HBr = 1 mol * 80.9 g/mol

Mass HBr = 80.9 grams

Step 5: Calculate ΔH

ΔH = m*c*ΔT

ΔH= (100 + 40 + 80.9) * 4.184 * (83-22.5)

ΔH= 220.9 * 4.184 * 60.5

ΔH= 55916.86 J = 55.92 kJ

Since this is an exothermic reaction, the change in enthalpy is negative.

ΔH = -55.92 kJ

4 0
4 years ago
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