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liubo4ka [24]
2 years ago
14

What is the oxidation state of C in NaHCO3? O A. +4 O B. -6 O C. +1 OD. -2

Chemistry
1 answer:
antiseptic1488 [7]2 years ago
8 0
<h2>Answer:    A (+4)</h2>

Explanation:

The HCO₃ in NaHCO₃ has an oxidation state of -1. We know this because of the charge on HCO₃ and also by the fact that Na is a group 1 metal that always has a +1 oxidation state.

The sum of the oxidation states of the components of HCO₃ has to be equal to -1

⇒  H + C + 3 O  =  - 1

     A rule of redox is that Oxygen always has a - 2 oxidation state and H usually has a + 1 oxidation state

⇒ 1  + C + 3(-2)  = - 1     <em>[make C the subject of the equation and simplify]</em>

⇒                   C = -1 - 1 + 6

                      C = + 4

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A large balloon contains 5400 m3 of He gas that is kept at a temperature of 280 K and an absolute pressure of 1.10 x 105 Pa. Fin
patriot [66]

Answer:

1.02 × 10⁶ g

Explanation:

Step 1: Given data

  • Volume of the balloon (V): 5400 m³
  • Temperature (T): 280 K
  • Absolute pressure (P): 1.10 × 10⁵ Pa
  • Molar mass of He (M): 4.002 g/mol

Step 2: Convert "V" to L

We will use the conversion factor 1 m³ = 1000 L.

5400 m³ × 1000 L/1 m³ = 5.400 × 10⁶ L

Step 3: Convert "P" to atm

We will use the conversion factor 1 atm = 101325 Pa.

1.10 × 10⁵ Pa × 1 atm / 101325 Pa = 1.09 atm

Step 4: Calculate the moles of He (n)

We will use the ideal gas equation.

P × V = n × R × T

n = P × V / R × T

n = 1.09 atm × 5.400 × 10⁶ L / 0.08206 atm.L/mol.K × 280 K

n = 2.56 × 10⁵ mol

Step 5: Calculate the mass of He (m)

We will use the following expression.

m = n × M

m = 2.56 × 10⁵ mol × 4.002 g/mol

m = 1.02 × 10⁶ g

8 0
2 years ago
The agent of mechanical weathering in which rock is worn away by the grinding action of other rock particles is call
Igoryamba

Physical weathering

3 0
3 years ago
A sample of 250 g of water are heated from 40°C to 121°C, calculate the amount of heat energy absorbed.
Marysya12 [62]

Answer:

the anwser isn't in the choices

Explanation:

H=MC(change of temp.)

M=mass of water=250g

C=specific heat of water = 4.186 j/g

change in temperature is 121-40= 81

H= 250x4.186x81=84766.5J

7 0
3 years ago
• How did your experimental absolute zero value compare to the accepted value?
Murrr4er [49]

The experimental absolute zero value is less when compared to the accepted value of absolute zero.

<h3>What is absolute zero?</h3>

Absolute zero is defined as the temperature in which the lowest energy possible is attained in a thermodynamic system.

Absolute zero temperature has an accepted values of 0 Kelvin or -273.15 degrees Celsius.

At absolute zero, it is assumed that the volume of an ideal gas becomes zero. However, it has not been possible to cool any gas to absolute zero.

Based on the graph of temperature against volume of gases, the experimental absolute zero extrapolated from the graph where volume of the gases becomes zero is -285 degrees Celsius.

Therefore, the experimental absolute zero value is less when compared to the accepted value.

Learn more about absolute zero at: brainly.com/question/1191114

#SPJ1

5 0
2 years ago
Please help!!
Olegator [25]
Molarity =  Moles/Liter

Use the molecular atomic mass of NaCl to convert from grams to moles.
Molecular mass of NaCl is the sum of its atomic masses. Look at the periodic table to find these. Na is 23 g/mol and Cl is 35.5 g/mol ,
so NaCl = 23 + 35.5 = 58.5 g/mol

multiply to cancel out grams
76 g NaCl * (1mol / 58.5 g NaCl) = 1.3 mol NaCl

over 1 Liter is just 1.3 M NaCl
Hope this helps!
8 0
3 years ago
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