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Anastasy [175]
3 years ago
9

In the nuclear transmutation represented by 168o(p, \alpha) 137n, the emitted particle is ________. in the nuclear transmutation

represented by o(p, \alpha) n, the emitted particle is ________. a beta particle. a proton. an alpha particle. a neutron. a positron.
Chemistry
1 answer:
ivolga24 [154]3 years ago
4 0

<span>Answer is: an alpha particle.</span>

<span>Nuclear reaction: ¹</span>⁶O + p⁺ → ¹³N + α (alpha particle).<span>
Alpha decay is radioactive decay in which an atomic nucleus emits an alpha particle (helium nucleus) and transforms into an atom with an atomic number that is reduced by two and mass number that is reduced by four.
When oxygen-16 gain one proton, atomic mass is 17, but when lose alpha particle atomic mass reduces by four to 13.</span>

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Answer:

Chemical nomenclature

3 0
3 years ago
What mass of a 4.00 % NaOH solution by mass contains 15.0 g of NaOH?
fenix001 [56]

Answer:

375 g

Explanation:

Let the total mass of the solution = x g

Given that the mass of NaOH in the solution = 15.0 g

Thus, mass of the solvent = x - 15.0 g

Given that the mass % of the solution = 4 %

So,

Mass\ percent=\frac {Mass\ of\ the\ solute}{Mass\ of\ the\ solution}\times 100

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4=\frac {15.0}{Mass\ of\ the\ solution}\times 100

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7 0
4 years ago
What current (in a) is required to plate out 1. 22 g of nickel from a solution of ni2 in 0. 50 hour?
Mashcka [7]

The current required to accumulate the 1.22 grams of nickel in 0.5 hours is 2.23 A.

<h3>What is current?</h3>

The current is given as the product of the charge with time. In the electrochemical analysis of the nickel, there will be a reduction of the nickel ion to nickel. The formation is given as:

\rm Ni^{2+}+2e^-\;\rightleftharpoons Ni

There is the deposition of 1 mole of Ni with 2 electrons transfer. The transfer of charge for 1 mole that is 58.7 grams Nickel is:

\rm 58.7\;g=2\;\times\;96487\;C\\58.7\;g=192974\;C

The mass of Ni to be deposited is 1.22 grams. The charge required is given as:

\rm 58.7\;grams\;Ni=192974\;C\\\\1.22\;grams\;Ni=\dfrac{192974}{58.7}\;\times\;1.22\;C\\\\1.22\;grams\;Ni=4010.7\;C

The current required to transfer 4010.7 C of charge in 1800 seconds is given as:

\rm Charge=Current\;\times\;Time\\4010.7\;C=Current\;\times\;1800\;sec\\Current=2.23\;A

Thus, the current required to accumulate the 1.22 grams of nickel in 0.5 hours is 2.23 A.

Learn more about current, here:

brainly.com/question/23063355

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7 0
2 years ago
A noncyclical alkane hydrocarbon containing eight carbon atoms should also contain eighteen hydrogen atoms.
Angelina_Jolie [31]
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5 0
4 years ago
How many grams of SO3 can be produced if 3.3 moles of O2 reacts?
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