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I am Lyosha [343]
3 years ago
6

Whats the answer for this

Mathematics
2 answers:
drek231 [11]3 years ago
7 0

Answer:

50/18 or 2.77

Step-by-step explanation:

So first u have to make the 3 1/3 and 1 1/5 into improper fractions.

Then, you can do the keep, change, flip thing and then u get 10/3 x 5/6 to get 50/18

dimaraw [331]3 years ago
5 0
50/18 or 2.77
u have to make the 3 1/3 and 11/5 into improper fractions
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The Bureau of Labor Statistics reported that the average yearly income of dentists in the year 2005 was $110,000. A sample of 81
Sholpan [36]

Answer:

a) We want to test to determine if there has been a significant increase in the average yearly income of dentists, the system of hypothesis would be:  

Null hypothesis:\mu \leq 110000  

Alternative hypothesis:\mu > 110000  

b) z=\frac{120000-110000}{\frac{36000}{\sqrt{81}}}=2.5    

c) p_v =P(Z>2.5)=0.0062  

We see that the p value is lower than the significance level of 1-0.95=0.05 so then we can conclude that the true mean is significantly higher than 110000 because we reject the null hypothesis.

Step-by-step explanation:

Information given

\bar X=12000 represent the sample mean for the yearly income in 2006 for the dentists

\sigma= 36000 represent the sample population deviation

n=81 sample size  

\mu_o =110000 represent the value that we want to test

\alpha=0.05 represent the significance level

z would represent the statistic

p_v represent the p value for the test

a) Hypothesis to verify

We want to test to determine if there has been a significant increase in the average yearly income of dentists, the system of hypothesis would be:  

Null hypothesis:\mu \leq 110000  

Alternative hypothesis:\mu > 110000  

Since we know the population deviation the statistic is given by:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

b) Statistic

When we replace the data given we got:

z=\frac{120000-110000}{\frac{36000}{\sqrt{81}}}=2.5    

c) P value

Now we can find the p value using the fact that we are conducting a right tailed test:

p_v =P(Z>2.5)=0.0062  

We see that the p value is lower than the significance level of 1-0.95=0.05 so then we can conclude that the true mean is significantly higher than 110000 because we reject the null hypothesis.

7 0
4 years ago
The product of (n2 – 6n + 3) and -4n is________ When this product is multiplied by -n, the result is________
krek1111 [17]
-4n^3+24n^2-12n, 4n^4-24n^3+12n^2
3 0
3 years ago
Read 2 more answers
Plz help me I need this by tomorrow morning ​
zhenek [66]

Answer: n/2, 4160/x

Step-by-step explanation:

n = 2t hence t = n/2

8 0
4 years ago
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