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Harrizon [31]
3 years ago
10

Pls help me solve this problem!!

Mathematics
1 answer:
ddd [48]3 years ago
4 0

Answer:

49.85

Step-by-step explanation:

41 is the mean, so half of the daily requests are above that number, half below, the question is about numbers above the mean, so the lower numbers won't be included in the percentage.

The difference between 59 and 41 is 18. The standard deviation given is 6.

18 ÷ 6 = 3  So that is 3 standard deviations. The empirical rule states that 99.7 of all values are within 3 standard deviations from the mean. But we are looking at only the upper half of those values so 99.7 ÷ 2 = 49.85 %

If the answer asks for approximate, you could round to 49.9 or 50.

And tell the math people to learn the correct spelling of fluorescent!

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Use the elimination method to solve the system of equations -x+5y=-4 and 4x+3y=16
jenyasd209 [6]

Answer:

A.(4,0)

Step-by-step explanation:

APEX

7 0
3 years ago
If you had half a dollar, three quarters, eight dimes, six nickels, and nine pennies, how much money would you have altogether?
hjlf

Answer:

$1.69

Step-by-step explanation:

Half a dollar = $0.50

Eight dimes = $0.80

Six nickels = $0.30

Nine pennies = $0.09

Total = $0.50 + $0.80 + $0.30 + $0.09 = $1.69

4 0
3 years ago
Evaluate the expression when t = –6.4 and u = –2.8.
denis-greek [22]
-6.4 – 4(-2.8)
-6.4 – - 11.2 = 4.8

Your answer is B: 4.8
7 0
3 years ago
Read 2 more answers
Find an equation of variation where y varies directly as x and y = 75 when x = 5, find y when x is 1.
Dafna11 [192]
<span>y=375/x, so when x=1, y=375</span>
7 0
3 years ago
Suppose a certain home improvement outlet knows that the monthly demand for framing studs is 2,300 when the price is $4.77 each
pogonyaev

Answer:

p + 0.0001q = 5

Step-by-step explanation:

Data provided in the question:

When Price, p₁ = $4.77 ; Demand, q₁ = 2,300

and,

When Price, p₂ = 3,300 ; Demand, q₂ = 3,300

considering the above as the points on the line,

now, the general equation for a line is given as:

\frac{q_1-q}{p_1-p}=\frac{q_2-q_1}{p_2-p_1}

on substituting the respective values, we get

\frac{2,300-q}{4.77-p}=\frac{3,300-2,300}{4.67-4.77}

or

\frac{2,300-q}{4.77-p}=\frac{1000}{-0.1}

or

2,300 - q = -10,000(4.77 - p)

or

⇒ 2,300 - q = -47700 + 10,000p

or

⇒ 10,000p + q = 2300 + 47700

or

⇒ 10,000p + q = 50000

or

⇒ p + 0.0001q = 5

8 0
3 years ago
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