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Svetradugi [14.3K]
3 years ago
9

The ocean surface is at 0 ft elevation. A diver is underwater at a depth of 138 ft. In this area, the ocean floor has a depth of

247 ft. A rock formation rises to a peak 171 ft above the ocean floor. How many feet below the top of the rock formation is the diver? I want to know how you would work this out.
Mathematics
2 answers:
Korvikt [17]3 years ago
7 0

We know that the ocean floor has a depth of 247 feet, and we also know that the diver is underwater at depth of 138 ft, so its distance from the ocean floor will be:

feet

Now, the rock formations rises to a peak 171 to above the ocean floor, so to find how many feet below the top of the rock formations is the diver, we are going to subtract the distance to the driver form the ocean floor from the rock formations height:

feet

We can conclude that the diver is 62 feet below the top of the rock formations.

hope it helps

ycow [4]3 years ago
3 0
The diver is 33 feet above the rock
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Barry has been watching the geese that live in his neighborhood. The number of geese changes each week. (n) f(n) (1) 56 (2) 28 (
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<u>Answer</u>

B. f(n) = 56(0.5)^n-1


<u>Explanation</u>

f(n) (1) 56

(2) 28

(3) 14

(4) 7

To find the correct relation we have to test all of them.

A. f(n) = 28(0.5)^n

f(1) = 28(0.5)¹

      = 28 × 0.5 = 14  

<em>f(n) = 28(0.5)^n ⇒  Not correct relation</em>

B. f(n) = 56(0.5)^n-1

    f(1) = 56(0.5)¹⁻¹  = 56×1

                              = 56

  F(2) = 56(0.5)²⁻¹  = 56 × 0.5  = 28

  F(3) = 56(0.5)³⁻¹  = 56 × 0.25 = 14

<em>  f(n) = 56(0.5)^n-1  ⇒ It is the correct relation</em>  

C. f(n) = 56(0.5)^n

   f(1) = 56(0.5)¹  = 56 × 0.5 = 28

<em>f(n) = 56(0.5)^n  ⇒ Not correct relation</em>

D. f(n) = 112(0.5)^n-1

  f(1) = 112(0.5)¹⁻¹  = 112 × 1 = 112

<em>f(n) = 112(0.5)^n-1   ⇒ Not correct relation</em>

4 0
3 years ago
Read 2 more answers
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