4 years ago

(5q - 8r) (5q + 8r) Multiplying polynomials

1 answer:

8 0

Hi!

This problem is pretty simple it is the factored form of a difference of squares expression.

The answer is 25q²-64r²

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sp2606 [1]

The expression can be solved by expanding the bracket and multiplying out the terms

$(p^4-q^4)(p^4+q^4)$ $\begin{gathered} =p^4(p^4+q^4)-q^4(p^4+q^4) \\ =p^8+p^4q^4-p^4q^4-q^8 \\ =p^8-q^8 \end{gathered}$

Therefore, the expression can be simplified as;

$p^8-q^8$

Alternatively, using the theorem of difference of two squares, which is

$a^2-b^2=(a-b)(a+b)$

Hence,

$p^8-q^8=(p^4)^2-(q^4)^2$

7 0

1 year ago

julia-pushkina [17]

Answer:

1000

Step-by-step explanation:

bc i dont know thats why hope it helped

7 0

3 years ago

Marat540 [252]

Answer:

Step-by-step explanation:

7 0

3 years ago

Maurinko [17]

I think the answer is 3w over z to the power of 5

8 0

4 years ago

finlep [7]

Answer:

Bro

Step-by-step explanation:

5 0

3 years ago