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Pani-rosa [81]
2 years ago
11

Sheila has 11

Mathematics
1 answer:
RSB [31]2 years ago
5 0

Answer:

6

Step-by-step explanation:

11 1/2 = 11.5

2 1/4 = 2.25

11.5 ÷ 2.25= 5.11

she needs 6 containers because you round up 5.11 to 6.

if your doing the work in fractions rather decimals let me know and I can explain it that way too

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Nonamiya [84]
Y=radical 3
just cancel out the 2 on both sides
3 0
2 years ago
To win at LOTTO in a certain state, one must correctly select 6 numbers from a collection of 52 numbers (1 through 52). The orde
miv72 [106K]

Answer:

The answer is 20,358,520

Step-by-step explanation:

Selecting 6 numbers from a collection of 52 numbers regardless of order involves a combination.

Note: if regards was taken into order of selection, this would be a permutation.

Hence, the different 6 number selections out of 52 is

52C6 = 52! / [6!*(52-6)!]

= 52!/(6!*46!)

= 20,358,520

7 0
3 years ago
Pls answer just the answer
Viefleur [7K]

Answer:

588000

Step-by-step explanation:

if i am wrong pls tell me cause i think there's a different answer gl g

7 0
2 years ago
Read 2 more answers
For what values ​​does c have no solutions?
defon

Solve for c :

x⁴ + cx² + 100 = 0

cx² = -(x⁴ + 100)

c = - (x⁴ + 100)/x²

If x = 0, the right side is undefined and c would have no solution.

3 0
2 years ago
Given z1 = -3
trasher [3.6K]

Answer:

See explanation

Step-by-step explanation:

The given complex number are:

z_1=-3\sqrt{3}+3i

and

z_2=6\cos 150\degree+6i\sin 150\degree

When we rewrite z_1=-3\sqrt{3}+3i in complex form, we obtain;

z_1=r(\cos \theta+i\sin \theta)

where

r=\sqrt{(-3\sqrt{3})^2+3^2 }=\sqrt{36}=6

and

\theta=tan^{-1}(\frac{y}{x})

\implies \theta=tan^{-1}(\frac{-3\sqrt{3}}{3})=150\degree

Hence,

z_1=6(\cos 150\degree+i\sin 150\degree)

z_1=6\cos 150\degree+6i\sin 150\degree

Hence

z_1=z_2

8 0
3 years ago
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