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taurus [48]
3 years ago
11

If angle A B C is congruent to and C B D, find x. ABC (7x - 40) CBD (4x + 32)

Mathematics
1 answer:
gregori [183]3 years ago
5 0
∠ABC ≡ ∠CBD
7x - 40° = 4x + 32°
3x = 72°
x = 24°
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Write the ratio in the simplest form 3 cups of sugar to 27 cups of milk
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Answer: 3:27

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Write each ratio in the simplest form. (Note: remember the units of measurement, they must be the same!)
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Please help with this question
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What is the value of this expression when c = -4 and d = 10?
lianna [129]

The complete question is

"What is the value of this expression when c= -4 and d= 10?

1/4 (c^3+d²)

A.2

B.9

C.21

D.41"

The value of this expression when c = -4 and d = 10 will be option B 9.

<h3>What is a simplification of an expression?</h3>

Usually, simplification involves proceeding with the pending operations in the expression.

Simplification usually involves making the expression simple and easy to use later.

The given expression is

1/4 (c^3+d^2)\\\\1/4 ((-4)^3+(10)^2)\\\\1/4 ( -64 + 100)\\\\1/4 (36)\\\\9

Hence, the value of this expression when c = -4 and d = 10 will be option B 9.

Learn more about an expression here:

brainly.com/question/1249625

#SPJ1

6 0
2 years ago
You are given a list of students names and their test scores. Design a pseudocode that does the following:(a) Calculates the ave
Rashid [163]

Answer:

List_of_students = {};    //Structure array that contains the scores of students and Names

Number_of_students = size(List_of_students);

Average_score ;   //Variable Stores average score

Below_Average = [];   //That is initially filled with zeros  

Highest_score ; //Initialize variable to store highest score

for ( i = 0 ; i < Number_of_students; i = i + 1)

{

      Average_score  = Average_score + List_of_students(i);    

     if ( i = 15)

      {

        Average_score  = Average_score / Number_of_students;

      }

}

for ( j = 0; j < Number_of_students ; i = i + 1)

{

    if (   List_of_students(j)  < Average_score)

     {

         print( "student  %name got %score , List_of_students(j),          List_of_students(j) )

     }

}

Compare_Score = 0;   //Variable to compare score

for ( k = 0; K < Number_of_students; k = k+1)

{

     if ( List_of_students(k) => Compare_Score)

    {

        Compare_Score = List_of_students(k);

    }

}

Highest_Score = Compare_Score;

Step-by-step explanation:

4 0
3 years ago
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