Mindy is taking MA 385 this Fall and two sections are offered. She estimates that if
1 answer:
solution:
P(passed)=P(Dr. J and passed)+P(Dr. S and passed) =0.4*0.8+(1-0.4)*0.6=0.68
hence probability that she was enrolled in Dr. J's section given passed
=P(Dr. J and passed)/P(passed)=0.4x0.8/0.68=0.4706
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