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hoa [83]
2 years ago
6

Mindy is taking MA 385 this Fall and two sections are offered. She estimates that if

Mathematics
1 answer:
Leona [35]2 years ago
3 0

solution:

P(passed)=P(Dr. J and passed)+P(Dr. S and passed) =0.4*0.8+(1-0.4)*0.6=0.68

hence probability that she was enrolled in Dr. J's section given passed

=P(Dr. J and passed)/P(passed)=0.4x0.8/0.68=0.4706


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9. What is the solution to this equation?<br> 3x + 10 = 19
svp [43]
<h2>Answer:</h2>

This is a 2-step equation:

3x + 10 = 19\\\\3x = 9\\\\x = 3

The solution is <em>x = 3</em>.

6 0
2 years ago
Quick whoever gives the right answer gets brainliest
guapka [62]

Answer:

the amount of sales

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Please Help!!!!!!! No stupid answers
Pavel [41]
The answer to A. is 108cm or 1.08m

First convert 2m to cm:
2m x 100 = 200 cm
Next convert 6m to cm:
6m x 100 = 600 cm
Divide the height of the person by his/her shadow:
200cm ÷ 600cm = <span>0.33333333333 = .3</span>
Multiply 360cm by .3:
360cm x .3 = 108cm
108cm ÷ 100 = 1.08m

The answer to B. is 6.8 cm.

The scale seems a bit small... are you sure you don't mean 0.8 m?
a = length of actual car.
8.5 x 0.8 = 1 x a
6.8 = 1 x a
6.8 ÷ 1 = a
6.8 = a

If you did mean 0.8 m... the answer is 680 cm or 6.8 m.

a = length of actual car.
0.8m x 100 = 80cm
8.5 x 80 = 1 x a
680 = 1 x a
680 ÷ 1 = a
680 = a
680 ÷ 100 = 6.8
8 0
3 years ago
Find the slope of the line through each pair of points
ddd [48]
The answer is 27/23. The way you listed the answers is confusing so I’m not giving a letter. Because [17+10]/[17+6]= 27/23
5 0
2 years ago
Seven pieces of rope have an average (arithmetic mean) length of 68 centimeters and a median length of 84 centimeters. If the le
Svet_ta [14]

Answer:

The maximum possible length, in centimeters, of the longest piece of rope is 134 cm

Step-by-step explanation:

Let the seven pieces be a,b,c,d,e,f,g

Average of 7 pieces of ropes  =68

Average = \frac{\text{Sum of all lengths}}{\text{No. of pieces}}

68= \frac{\text{Sum of all lengths}}{7}

68 \times 7 =\text{a+b+c+d+e+f+g}

476=\text{a+b+c+d+e+f+g} --A

We are given that the median length of a piece of rope is 84 centimeters.

We arrange the pieces in the ascending order

So, median will be the length of 4th piece

So, d = 84 cm

the length of piece a,b,c will be less than 84 and the value of e,f,g must be greater than or equal to 84

Let us suppose the length of a,b,c be x

Let us suppose the length of e,f be 84

The length of the longest piece of rope is 14 centimeters more than 4 times the length of the shortest piece of rope

So, g = 4x+14

Substitute the value in A

476=x+x+x+84+84+84+4x+14

476=7x+266

\frac{476-266}{7}=x

30=x

g = 4x+14=4(30)+14=134

Hence the maximum possible length, in centimeters, of the longest piece of rope is 134 cm

7 0
2 years ago
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