Question

Mindy is taking MA 385 this Fall and two sections are offered. She estimates that if

Answer 1

solution:

P(passed)=P(Dr. J and passed)+P(Dr. S and passed) =0.4*0.8+(1-0.4)*0.6=0.68

hence probability that she was enrolled in Dr. J's section given passed

=P(Dr. J and passed)/P(passed)=0.4x0.8/0.68=0.4706