Question

∆ABC is reflected about the line y = -x to give ∆A'B'C' with vertices

Answer 1

Well you have to change the first number in ALL of the () so 

(-1,1) = (1,1)

(-2,-1) = (2,-1)

(-1,0) = (1,0)

so your answer is d (1, 1), B(2, -1), C(1, 0)

Answer 2

Answer:

b. A(-1, 1), B(1, 2), C(0, 1)

Step-by-step explanation:

Reflecting across the line y = -x switches the x- and y-coordinates and negates them.  Algebraically, it maps every point (x, y) → (-y, -x).

This means that for A'(-1, 1), -y = -1 and -x = 1; this means y = 1 and x = -1, so A is (-1, 1).

For B'(-2, -1), -y = -2 and -x = -1; this means y = 2 and x = 1, so B is (1, 2).

For C'(-1, 0), -y = -1 and -x = 0; this means y = 1 and x = 0, so C is (0, 1).