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Pavlova-9 [17]
3 years ago
13

Factorise: t3+t2+t+1

Mathematics
1 answer:
zloy xaker [14]3 years ago
7 0

T6+1. you just need to add the same factors (T in this example) and since 1 doesn't have a "friend" it will be alone

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Which rational number is one tick mark to the right of Negative StartFraction 6 Over 4 EndFraction on the number line below?
valina [46]

We want to determine the rational number which is one tick mark to the left of =

- 3 / 4

If the number is to the left, it must be less than =

- 3/4

Since there are 4 equal spaces between each number, the numbers between -1 and 0 are =

-1, 3/4, 2/4, 1/4, 0.

We can then see that the number one tick to the left of =

- 3/4 is -1.

<u><em>B.</em></u>

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<u><em></em></u>Goesy<u><em></em></u>

4 0
3 years ago
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The population growth of two towns over a period of five years is represented by the system of equations below, both algebraical
Andreas93 [3]

Answer:

(4, 10)

Step-by-step explanation:

Hope this helps

3 0
3 years ago
N is an integer -1 &lt; n &lt; 4 list the possible values of n
Akimi4 [234]
Look at the picture. The only integer numbers meeting the given condition are 0,1,2,3.

So n=\{0,1,2,3\} 

7 0
3 years ago
Two groups of friends go to a movie. Each ticket costs the same amount. One group spends ​$57. The other group spends ​$95. List
kenny6666 [7]

Answer:

1) All possible number tickets for group that spends $57: A, B, C, D

2) All possible number tickets for group that spends $95: B, C, E, F

3) Each ticket will cost at most $19

Step-by-step explanation:

We are told that one group spends $57 dollars while the other group spends $95.

Now,we want to find all possible whole number ticket prices for each group and at most how much each ticket​ costs.

To do this, let's first find the factors of both amounts which will give us all possible whole number ticket prices for each group.

57: 1, 3, 19, 57

95: 1, 5, 19, 95

Since each ticket costs same amount, to find out at most how much each ticket costs, we will select the highest common factor of both groups which is 19.

Thus,each ticket will cost at most $19

8 0
3 years ago
A sector with an area of \goldE{48\pi,\text{cm}^2}48πcm 2 start color #a75a05, 48, pi, start text, c, m, end text, squared, end
erik [133]

Answer:

3/8 π radians

Step-by-step explanation:

The Area of a sector when then central angle is in radians = 1/2r² θ

Where

θ = central angle = ?

r = 16 cm

Area of the sector = 48πcm²

Hence

Central angle = Area of a sector ÷ (1/2r²)

= 48πcm² ÷ (1/2 × 16²)

= 48πcm² ÷ 128

Central angle = 3/8π radians

Therefore, Central angle = 3/8π radians

7 0
3 years ago
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