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Pavlova-9 [17]
3 years ago
13

Factorise: t3+t2+t+1

Mathematics
1 answer:
zloy xaker [14]3 years ago
7 0

T6+1. you just need to add the same factors (T in this example) and since 1 doesn't have a "friend" it will be alone

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A special liquid is held in a tank described as (x 2 + y 2 ) ≤ z ≤ 1 in a Cartesian coordinate system. Assume that the density o
vivado [14]

Since \rho=\dfrac mV (density = mass/volume), we can get the mass/weight of the liquid by integrating the density \rho(x,y,z) over the interior of the tank. This is done with the integral

\displaystyle\int_{-1}^1\int_{-\sqrt{1-x^2}}^{\sqrt{1-x^2}}\int_{x^2+y^2}^1(2-z^2)\,\mathrm dz\,\mathrm dy\,\mathrm dx

which is more readily computed in cylindrical coordinates as

\displaystyle\int_0^{2\pi}\int_0^1\int_{r^2}^1(2-z^2)r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta=\boxed{\frac{3\pi}4}

7 0
3 years ago
A school dedicated 20% of the courtyard area for students to start a garden. The students want to know how much of the 950-squar
Step2247 [10]

Answer:

190 square foot

Step-by-step explanation:

School yard = 950 square foot

20% of school yard for student to start garden

Therefore

20/100 x 950

= 190 square foot

7 0
3 years ago
Find the solution to this equation 2(x + 12) - 2x = 3(x - 2)
Wewaii [24]

Answer:

it equals x=10 so i guess it's B

Step-by-step explanation:

6 0
3 years ago
4. Andrés desea embaldosar el piso de su casa que tiene 375 cm de ancho y 435 cm de largo. Calcula la longitud del lado que tend
svetlana [45]

Answer:

Sabemos que el piso es un rectángulo de 435 cm de largo y 375 cm de ancho.

Recordar que para un rectángulo de largo L, y ancho W, el área es:

A = L*W

Entonces el área del piso, será:

A = 435cm*375cm = 163,125 cm^2

Primero, sabemos que se utilizaran baldosas (las cuales son cuadradas) y queremos saber la longitud de lado que tendrían las baldosas.

No tenemos ningún criterio para encontrar este lado, solo que (si queremos usar un número entero de baldosas) el largo L del lado de la baldosa deberá ser un divisor de tanto el ancho como el largo del suelo.

Dicho de otra forma

el largo, 435cm, tiene que ser múltiplo de L

el ancho, 375cm, tiene que ser múltiplo de L.

Por ejemplo, ambos números son múltiplos de 5, entonces podríamos tomar L = 5cm

En este caso, el área de cada baldosa es:

a = L^2 = 5cm*5cm = 25cm^2

Y el número total de baldosas que necesitaría usar esta dado por el cociente entre el área del suelo y el area de cada baldosa.

N = ( 163,125 cm^2)/(25cm^2) = 6,525 baldosas.

También sabemos que ambos números (435cm y 375cm) son múltiplos de 15cm

Entonces las baldosas podrían tener 15cm de lado.

En este caso, el área de cada baldosa es:

A = (15cm)^2 = 225cm

En este caso el número total de baldosas necesarias será:

N =  ( 163,125 cm^2)/(225cm^2) = 725 baldosas.

5 0
3 years ago
Help with these questions
balandron [24]

9514 1404 393

Answer:

  16) No

  17)  (c)

Step-by-step explanation:

For a lot of multiple-choice matrix problems, a simple test is all that is needed to determine the correct answer.

16) The determinant of A is (-2)(-2) -(2)(-3) = 10. So, we expect to see values in the inverse matrix that are 0.2 and 0.3. Alas, they're not there. The matrices are not inverses.

  A^-1 = [[-.2, .3][-.2, -.2]]

__

17) The matrices are both 3×3, so their product is possible (eliminates choice D). The upper left term is different among the answer choices, so we can determine the correct one by computing that term only.

  BA=C

  c11 = (5)(1) +(7)(5) +(3)(-1) = 5 +35 -3 = 37

This matches the third choice (C).

If you use a calculator to compute the full matrix product, it matches choice C in all details.

6 0
3 years ago
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