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Alex17521 [72]
3 years ago
11

Could somebody please answer this?

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
3 0
Here are the resulting percentages:
LEAH = 3.5%
RATHA = 2.3%
ED = 1.8%
CHRIS = 4.2%
MARY = 2.5%

You arrive at this answer by dividing the bonus by the wages

BONUS/WAGE = PERCENTAGE OF BONUS TO WAGE.

Chris had the greatest percentage of wages in his bonus
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A train leaves Philadelphia at 2:00 PM. A second train leaves the same city in the same direction at 4:00 PM. The second train t
polet [3.4K]

Answer: First train speed shall be 42 mi/hr

Second train speed shall be 84 mi/hr

Yes it is the valid answer, it gets annoying when almost everyone enters the wrong answer for a good laugh. Either way, hope this helps! Have a spectacular day.

Step-by-step explanation:

What is the 1st train's head start in miles?

Let +s+ = the speed of the 1st train in mi/hr

From 2PM to 4PM is 2 hrs

+d%5B1%5D+=+s%2A2+

---------------------

Let +d+ = distance the 2nd train travels until

it overtakes the 1st train

From 4PM to 6PM is 2 hrs

Start time when the 2nd train leaves

---------------------

Equation for 1st train:

(1) +d+-+2s+=+s%2A2+

Equation for 2nd train:

(2) +d+=+%28+s%2B42+%29%2A2+

--------------------

Substitute (2) into (1)

(1) +%28+s%2B42+%29%2A2+-+2s+=+s%2A2+

(1) +2s+%2B+84+-+2s+=+2s+

(1) +2s+=+84+

(1) +s+=+42+

and

+s%2B+42+=+42+%2B+42+

+s+%2B+42+=+84+

------------------

The 1st train's speed is 42 mi/hr

The 2nd train's speed is 84 mi/hr

---------------------------

check:

(2) +d+=+%28+s%2B42+%29%2A2+

(2) +d+=84%2A2+

(2) +d+=+168+

and

(1) +d+-+2s+=+s%2A2+

(1) +d+-+2%2A42+=+42%2A2+

(1) +d+=+84+%2B+84+

(1) +d+=+168+

8 0
2 years ago
Solve the problem. Make sure your answer is in simplest form and improper fractions are expressed as mixed numbers.
pogonyaev
22/5=4 and 2/5

27/9= 3 wholes
5 0
2 years ago
Read 2 more answers
What is the value of X? <br> x/5+6=36<br> X=?
Nonamiya [84]
<span><span> STEP 1. </span><span><span>x/5+6= 36
 STEP 2. x/5 = 30
STEP TRES  x= 150</span> </span></span>
6 0
3 years ago
Solve for question C
Mariana [72]
The correct answer is x=4

8 0
3 years ago
Read 2 more answers
A man throws a ball off the top of a building and records the height of the ball at different times as shown in the table:
expeople1 [14]
A.) y = ax^2 + bx + c
46 = a(0)^2 + b(0) + c
c = 46

63 = a(1)^2 + b(1) + 46
a + b = 17 . . . (1)

48 = a(2)^2 + b(2) + 46
4a + 2b = 2
2a + b = 1 . . . (2)

1 = a(3)^2 + b(3) + 46
9a + 3b = -45
3a + b = -15 . . . (3)

(1) - (2) = (2) - (3) => -a = 16
a = -16
From (1), b = 17 + 16 = 33

The required model is y = -16t^2 + 33t + 46

b.) for t = 2.5: y = -16(2.5)^2 + 33(2.5) + 46 = -16(6.25) + 82.5 + 46 = -100 + 128.5 = 28.5
Therefore, the height of the ball at 2.5 seconds is 28.5 feet.

c.) At maximum height, dy/dt = 0
dy/dt = -32t + 33 = 0
t = 33/32 = 1.03125
Maximum height = -16(1.03125)^2 + 33(1.03125) + 46 = 63.015625 ≈ 63 feet.
8 0
2 years ago
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