Answer: if the pressure in the container is doubled, then the temperature will double too.
Justification:
You can rely on Gay-Lussac's law for ideal gases to answer the question.
According to that law, the pressure and temperature of a fixed amount of gas in a closed rigid container (constant volume) varie in direct proportion.
Mathematically, you can write in this way:
P/T = k
P₁ / T₁ = P₂ / T₂
That means, that if the pressure in the container is doubled, then the temperature will double too.
You can see that mathematically:
P₂ = 2 P₁
T₂ = (T₁ / P₁)(P₂) = (T₁ / P₁) (2 P₁) = 2 T₁
