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Stella [2.4K]
1 year ago
10

Which planet moves the fastest and which planet moves slowest? a, b, c, d, e, or f. Explain

Physics
1 answer:
Alisiya [41]1 year ago
6 0
D is the point where the planet moves the fastest. This is because it is in the perihelion, where the planet is moving at it’s fastest pace
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The energy of a photon is proportional to its a) amplitude. d) wave number, k-2m/A c) velocity. b) frequency
Scilla [17]

Answer:

Frequency

Explanation:

Photons are the packet of energy. They are massless and chargeless particles. They travel in the vacuum with the speed of light. The energy of photon is given by :

E=h\nu

Where

h = Planck's constant

\nu = frequency of photon

Or E=\dfrac{hc}{\lambda}

c = speed of light

\lambda = wavelength of photon

From the above equation, it is clear that the energy of photon is directly proportional to its frequency.

5 0
3 years ago
Fill in the blanks to complete each statement about the heating of Earth's surface.
cricket20 [7]

Answer:

absorption and insolation.

Explanation:

6 0
3 years ago
Lab: Thermal Energy Transfer What is the purpose of the lab, the importance of the topic, and the question you are trying to ans
VladimirAG [237]

Answer:

it's important because it shows how thermal energy transforms or continues to be all around us in everything

6 0
2 years ago
A playground merry-go-round has a mass of 115 kg and a radius of 2.50 m and it is rotating with an angular velocity of 0.520 rev
tatuchka [14]

Answer:

W_f = 2.319 rad/s

Explanation:

For answer this we will use the law of the conservation of the angular momentum.

L_i = L_f

so:

I_mW_m = I_sW_f

where I_m is the moment of inertia of the merry-go-round, W_m is the initial angular velocity of the merry-go-round, I_s is the moment of inertia of the merry-go-round and the child together and W_f is the final angular velocity.

First, we will find the moment of inertia of the merry-go-round using:

I = \frac{1}{2}M_mR^2

I = \frac{1}{2}(115 kg)(2.5m)^2

I = 359.375 kg*m^2

Where M_m is the mass and R is the radio of the merry-go-round

Second, we will change the initial angular velocity to rad/s as:

W = 0.520*2\pi rad/s

W = 3.2672 rad/s

Third, we will find the moment of inertia of both after the collision:

I_s = \frac{1}{2}M_mR^2+mR^2

I_s = \frac{1}{2}(115kg)(2.5m)^2+(23.5kg)(2.5m)^2

I_s = 506.25kg*m^2

Finally we replace all the data:

(359.375)(3.2672) = (506.25)W_f

Solving for W_f:

W_f = 2.319 rad/s

7 0
3 years ago
Analyze the effects on a passenger riding in a car traveling at
Mamont248 [21]

Without:

  • The passenger will get seriously injured
  • Colliding with the windshield at 50km/h
  • Could result in death

With safety:

  • The seatbelt holds tge passengers body back so they dont collide with anything
  • Their head is cushioned by the airbag
  • The passenger might get minor injuries but nothing serious will happen
5 0
2 years ago
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