1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
VikaD [51]
3 years ago
5

56/h +3y for h =4 and y =3

Mathematics
2 answers:
BARSIC [14]3 years ago
5 0
My answer would be 23
Cerrena [4.2K]3 years ago
5 0

Answer:

23 is the answer.

Step-by-step explanation:

Step 1- Substitute the variables.

56/4+ 3(3)

Step 2- Divide and multiply to simplify the equation.

14+9

Step 3- Add

14+9= 23

You might be interested in
What does it mean if the slopes are different
gladu [14]

Answer:

it means that they are 2 different lines on a cordinate plane

PLZ MARK BRAINLIEST

4 0
3 years ago
Read 2 more answers
a slitter assembly contains 48 blades five blades are selected at random and evaluated each day for sharpness if any dull blade
son4ous [18]

Answer:

P(at least 1 dull blade)=0.7068

Step-by-step explanation:

I hope this helps.

This is what it's called dependent event probability, with the added condition that at least 1 out of 5 blades picked is dull, because from your selection of 5, you only need one defective to decide on replacing all.

So if you look at this from another perspective, you have only one event that makes it so you don't change the blades: that 5 out 5 blades picked are sharp. You also know that the probability of changing the blades plus the probability of not changing them is equal to 100%, because that involves all the events possible.

P(at least 1 dull blade out of 5)+Probability(no dull blades out of 5)=1

P(at least 1 dull blade)=1-P(no dull blades)

But the event of picking one blade is dependent of the previous picking, meaning there is no chance of picking the same blade twice.

So you have 38/48 on getting a sharp one on your first pick, then 37/47 (since you remove 1 sharp from the possibilities, and 1 from the whole lot), and so on.

Also since are consecutive events, you need to multiply the events.

The probability that the assembly is replaced the first day is:

P(at least 1 dull blade)=1-P(no dull blades)

P(at least 1 dull blade)=1-(\frac{38}{48}* \frac{37}{47} *\frac{36}{46}*\frac{35}{45}*\frac{34}{44})

P(at least 1 dull blade)=1-0.2931

P(at least 1 dull blade)=0.7068

5 0
3 years ago
3x-2&gt;4<br> What’s the answer
Oxana [17]

Answer:

2

Step-by-step explanation:

3 0
3 years ago
The 1 mile race is equal to how many feet
Elina [12.6K]

Answer:

5280 ft

Step-by-step explanation:

1 mile = 5280 ft

8 0
3 years ago
Can someone give me an answer for this?
stealth61 [152]

Answer:

444 adult ticket

763 student ticket

Step-by-step explanation:

let a = number of adult ticket

let s = number of student ticket

s+a=1207

5a+s=2983

get s by itself in the 1st equation so you can plug it into the 2nd

s+a=1207

-a      -a

s=1207-a

5a+(1207-a)=2983

solve for a

4a+1207=2983

-1207      -1207

4a= 1776

444

this is adult ticket amount

subtract this from 1207 to get student amount

1207-444=763

8 0
3 years ago
Other questions:
  • 5ab-2 with positive exponents
    15·1 answer
  • -3 17/20 as a decimal
    10·1 answer
  • You drive your car for 4.5 hours at an average speed of 70 miles per hour how far did you go
    12·1 answer
  • Three times each day, a quality engineer samples a component from a recently manufactured batch and tests it. Each part is class
    14·1 answer
  • 3)
    10·1 answer
  • If a card is drawn at random from a standard 52-card deck, what is the probability that
    11·1 answer
  • Round to the nearest tenth , if necessary.<br><br> 65% of 186 =
    6·2 answers
  • Find the perimeter of a circle with radius 35 cm<br><img src="https://tex.z-dn.net/?f=%28take%20%20%5Cpi%20%3D%2022%20%207%20%5C
    13·2 answers
  • 7x^2 -3x-6<br> 7x <br> 2<br> −3x−6
    5·1 answer
  • What are the sales taxes on the state level collected for
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!