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3 years ago

Y = 2x + 4 y = 3x +2 Graph and give me the points of this linear equation

1 answer:

7 0

Y=2x+4 would start at the y intercept of 4, so (0,4) then go up 2 since it’s a positive slope and go over one, up two over one. And repeat.

Y=3x+2 would start at the y intercept of 2 and go up 3 over 1 and repeat, then graph the line!

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2 years ago

Read 2 more answers

Need to write steps and solve thanks

nalin [4]

Answer:

The coordinates of endpoint V is (7,-27)

Solution:

Given that the midpoint of line segment UV is (5,-11) And U is (3,5).

To find the coordinates of V.

The formula for mid-point of a line segment is as follows,

Midpoint of UV is $\frac{x_{1}+x_{2}}{2}$ , $\frac{y_{1}+y_{2}}{2}$

As per the formula, $\frac{x_{1}+x_{2}}{2}$ =5, $\frac{y_{1}+y_{2}}{2}$ =-11

Here $x_{1}=3; y_{1}=5$

Substituting the value of $x_{1}$ we get,

$\frac{3+x_{2}}{2}$ =5

$3+x_{2}=5\times2$

$x_{2}=10-3$

$x_{2}=7$

Substituting the value of $x_{2}$ we get,

$\frac{5+y_{2}}{2}$ =-11

$5+y_{2}=-11\times2$

$y_{2}=-22-5$

$y_{2}=-27$

So, the coordinates of V is (7,-27)

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2 years ago

How many solutions does this linear system have?

gayaneshka [121]

Answer:

One solution: (2.5,0)

Step-by-step explanation:

We can use substitution for the solution. Substitute y=2x-5 to -8x-4y=-20 so that you end up with -8x-8x+20=-20. Next you want to add like terms which will be -16x+20=-20, next you want isolate x by subtracting 20 from both sides and leaves you with -16x=-40. Divide -16 on both sides to fully isolate x and will leave you with x=2.5. Now substiture in 2.5 for x in y=2x-5 to get y=2(2.5)-5 which will then lead to y=0.

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3 years ago

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charle [14.2K]

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When proofreading, you should make sure all details are accurate and writing mechanics are correctly used.

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3 years ago

A ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is h-48t -16t^2.

Marat540 [252]

Answer:

36 feet.

Step-by-step explanation:

We have been given that a ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is $h(t)=-48t -16t^2$ . We are asked to find the maximum height of the ball.

We can see that our given equation is a downward opening parabola, so its maximum height will be the vertex of the parabola.

To find the maximum height of the ball, we need to find y-coordinate of vertex of parabola.

Let us find x-coordinate of parabola using formula $x=-\frac{b}{2a}$ .

$x=-\frac{-48}{2(-16)}$

$x=-\frac{48}{32}$

$x=-\frac{3}{2}$

So, the x-coordinate of the parabola is $-\frac{3}{2}$ . Now, we will substitute $x=-\frac{3}{2}$ in our given equation to find y-coordinate of parabola.