Answer: c. 39.14 to 42.36
Step-by-step explanation:
We want to determine a 95% confidence interval for the average hourly wage (in $) of all information system managers
Number of sample, n = 75
Mean, u = $40.75
Standard deviation, s = $7.00
For a confidence level of 95%, the corresponding z value is 1.96. This is determined from the normal distribution table.
We will apply the formula
Confidence interval
= mean +/- z ×standard deviation/√n
It becomes
40.75 +/- 1.96 × 7/√75
= 40.75 ± 1.96 × 0.82
= 40.75 + 1.6072
The lower end of the confidence interval is 40.75 - 1.6072 =39.14
The upper end of the confidence interval is 40.75 + 1.6072 =42.36
Answer:
D
Step-by-step explanation:
There 2 ways to interpret this problem.
From the info given:
These two triangles are congruent by SSS and congruent triangles have congruent or equal side lengths so the answer have to be 1.
If the triangles are similar, the side lengths form a proportion of that
So the ratio or scale factor is 1.
It is 5.9 meters and 590 centimeters
2125 started.....94.12% finished
94.12% of 2125 =
0.9412(2125) = 2000.05 finished
