Answer:
10.5618feet, 0.8125sec
Step-by-step explanation:
Given the height reached by the catapult expressed by the equation H=-16T^2+26T
At the maximum height, the velocity of the object is zero, hence;
v = dh/dt = 0
-32t + 26 = 0
-32t = -26
t = 26/32
t = 0.8125secs
Hence it will attain the maximum height after 0.8125second
Substitute t = 0.8125s into the expression to get the maximum height
H=-16t^2+26t
H = -16(0.8125)^2 + 26(0.8125)
H = -16(0.6602) + 21.125
H = -10.5632+21.125
H = 10.5618
hence the maximum height reached by the ball is 10.5618feet
<span><span>so assuming the sum of the shortest distance added to exactly the longest distance,
We could not be off by more than.
is the sum,
and it differs from by,
so the points are not colinear.</span><span>
</span></span>
Answer:Since both terms are perfect squares, factor using the difference of squares formula,
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Step-by-step explanation:
Answer:
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Step-by-step explanation:
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Answer:
Step-by-step explanation:
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