I possibly think it is c that is what I got
Answer:
NUMBER 1.)
Step 1
Subtract 3y3y from both sides.
5x=10-3y5x=10−3y
Step 2
Divide both sides by 55.
\frac{5x}{5}=\frac{10-3y}{5}
5
5x
=
5
10−3y
Hint
Undo multiplication by dividing both sides by one factor.
Step 3
Dividing by 55 undoes the multiplication by 55.
x=\frac{10-3y}{5}x=
5
10−3y
Hint
Undo multiplication.
Step 4
Divide 10-3y10−3y by 55.
x=-\frac{3y}{5}+2x=−
5
3y
+2
Hint
Divide.
Solution
x=-\frac{3y}{5}+2x=−5
3y+2
Step-by-step explanation:
NUMBER 2.)
Step 1
Add 4y4y to both sides.
3x=6+4y3x=6+4y
Step 2
The equation is in standard form.
3x=4y+63x=4y+6
Step 3
Divide both sides by 33.
\frac{3x}{3}=\frac{4y+6}{3}
3
3x
=
3
4y+6
Hint
Undo multiplication by dividing both sides by one factor.
Step 4
Dividing by 33 undoes the multiplication by 33.
x=\frac{4y+6}{3}x=
3
4y+6
Hint
Undo multiplication.
Step 5
Divide 6+4y6+4y by 33.
x=\frac{4y}{3}+2x=
3
4y
+2
Hint
Divide.
Solution
x=\frac{4y}{3}+2x= 3
4y+2
Answer:
12/5 or 2.4 cm³
Step-by-step explanation:
3*4/3*3/5=12/5 or 2.4 cm³
