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Usimov [2.4K]
3 years ago
11

Hello, I just wanted to ask someone to correct my work and to check if everything is correct. Thank you!

Physics
2 answers:
IrinaVladis [17]3 years ago
6 0

it look like everyting its correct


Naddika [18.5K]3 years ago
3 0

yes everything is right

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If the Moon rises at a given location at 6:00 p.m. today, about what time will it rise tomorrow night?
Lena [83]

Answer:

6:50 PM

Explanation:

The Moon continually moves on ahead in its orbit while the Earth rotates. So 24 hours after, the Earth has rotated back around to the same place it was the night before, while the Moon has gone on ahead. assume of it like the second hand on an analog watch, it’s going around the face of the clock much faster than the minute hand, but each time the second hand goes around, the minute hand has moved, and so it takes an extra second to line back up with the minute hand. Because the Moon has moved 13 degrees or so since its last moon rise, it’s going to take another hour or so for the Earth to catch back up to the Moon’s new location, delaying the Moon's rising above your horizons by ~50 minutes each day.

3 0
3 years ago
Someone help me with letter d. and e. I’m supposed to solve for y.
Bumek [7]

Answer:

t=\frac{a}{\sqrt{1-\frac{y^2}{c^2}}}\\\frac{y^2}{c^2}=1-\frac{a^2}{t^2}\\y^2=\frac{c^2t^2-c^2a^2}{t^2}\\y=\frac{c}{t}\sqrt{t^2-a^2}

t=\frac{a}{\sqrt{1-\frac{v^2}{y^2}}}\\\frac{v^2}{y^2}=1-\frac{a^2}{t^2}\\\\\frac{v^2}{y^2}=\frac{t^2-a^2}{t^2}\\y^2=\frac{v^2t^2}{t^2-a^2}\\y=\frac{vt}{\sqrt{t^2-a^2}}

7 0
3 years ago
A copper wire 12 cm long and a mass of 16 g is in a magnetic field of 1.2 T oriented perpendicular to the wire. What current wou
Ugo [173]

Answer:

Current, I = 1.08 A

Explanation:

Given that,

Length of the copper wire, l = 12 cm = 0.12 m

Mass of the wire, m = 16 g = 0.016 kg

Magnetic field, B = 1.2 T

The magnetic field is oriented perpendicular to the wire. We need to find the current in the wire.

Magnetic force, F = BIL

Force of gravity, F' = mg

F' = F

BIL=mg

I=\dfrac{mg}{BL}

I=\dfrac{0.016\times 9.8}{1.2\times 0.12}

I = 1.08 A

So, the current through the wire is 1.08 A. Hence, this is the required solution.

8 0
4 years ago
What is the equation used to find the speed of an object?
Alex_Xolod [135]
Speed(S) = Distance(d) ÷ Time(t)

S = d/t
6 0
4 years ago
A 6.0-kg ball is sliding to the right at 25.0m/s and strikes a second ball (15-kg) that is initially at rest head-on. After the
katrin [286]

Answer:

15 m/s to the right

Explanation:

Let's say right is positive and left is negative.

Momentum is conserved:

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(6.0 kg) (25.0 m/s) + (15 kg) (0 m/s) = (6.0 kg) (-12.5 m/s) + (15 kg) v₂

v₂ = 15 m/s

5 0
3 years ago
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