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oksano4ka [1.4K]
3 years ago
8

How do similar (S-S or N-N) magnetic poles interact?

Physics
2 answers:
maks197457 [2]3 years ago
7 0
A they repel each other
sineoko [7]3 years ago
4 0
They repel each other.
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An object moves with velocity v(t)=t^2-8t+7
solong [7]
<span>a) write a polynomial expression for the position of the particle at any time t greater or equal to zero. 
</span>Position is found by integrating velocity: 

<span>s(t) = (t^3)/3 - 4t^2 + 7t + c 
</span>where c is a constant corresponding to the position at t=0. <span>

b) at what time(s) is the particle changing direction
</span>the particle changes direction whenever the velocity is zero; the velocity function equals 

<span>(t-1)(t-7) a difference of squares so the zeros are 1 and 7, it changes direction at 1 second and 7 seconds. </span><span>

c) find the total distance traveled by the particle from t=0 and t=4
</span><span>s(0) = c
s(1) = 8/3 + c
s(4) = 64/3 - 64 + 28 + c. 
</span>
from 0 to 1 the particle travels 8/3 units. From 1 to 4 it travels -(64/3 - 36 - 8/3) = (-(56/3 - 108/3)) 
<span>=-(-52/3) = 52/3 units 
</span>
<span>so in total it travels 52/3 + 8/3 =20 units</span>
6 0
3 years ago
Please answer the following question.
Elina [12.6K]

Doppler Shift lets you see a star A. Move back and forth

<h3>What is Doppler Shift?</h3>

This refers to the frequency change of a wave in relation to an observer as it moves back and forth.

Hence, we can see that the thing which astronomers can learn from the Radial Velocity Method is D. Period of orbit and minimum mass of a planet as it measures the wavelengths of absorption lines in its spectrum.

Read more about doppler shift here:

brainly.com/question/4052291

#SPJ1

7 0
2 years ago
In the 1920s what did Edmund hubble notice about the galaxies
zlopas [31]
Hubble noticed that the galaxies were moving away from us, which meant the universe was expanding.

This is why constellations change over time. In some years, the Big Dipper won't actually look like a dipper anymore.
5 0
3 years ago
An 800 kHz radio signal is detected at a point 3.2 km distant from a transmitter tower. The electric field amplitude of the sign
hammer [34]

Answer:

1.07 nT

Explanation:

We know that E/B = c where E = electric field amplitude = 320 mV/m = 0.32 V/m, B = magnetic field amplitude and c = speed of light = 3 × 10⁸ m/s.

So, B = E/c

Substituting E and c into B, we have

B = E/c

= 0.32 V/m ÷ 3 × 10⁸ m/s

= 0.1067 × 10⁻⁸ T

= 1.067 × 10⁻⁹ T

= 1.067 nT

≅ 1.07 nT

3 0
3 years ago
What uniform magnetic field, applied perpendicular to a beam
schepotkina [342]

Answer:

The magnetic field is 2.11\times10^{-5}\ T

Explanation:

Given that,

Speed v=1.30\times10^{6}\ m/s

Radius = 0.350 m

We need to calculate the magnetic field

Using formula of magnetic field

B =\dfrac{mv}{qr}

Where, m = mass of electron

v = speed of electron

q = charge of electron

r = radius

Put the value into the formula

B=\dfrac{9.1\times10^{-31}\times1.30\times10^{6}}{1.6\times10^{-19}\times0.350}

B=2.11\times10^{-5}\ T

Hence, The magnetic field is 2.11\times10^{-5}\ T

5 0
4 years ago
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