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Fittoniya [83]
3 years ago
6

Ligaments are important because they provide joints with:

Physics
1 answer:
lora16 [44]3 years ago
4 0

Answer:

the answer is B. it's too easy

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Ancient peoples both feared and revered Solar and Lunar Eclipses as they happened so rarely. Explain the following about eclipse
podryga [215]

Answer:

Why is a solar eclipse more rare than a lunar eclispes.

Explanation:

7 0
3 years ago
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You prepare tea with 0.250 kg of water at 85.0 ºC and let it cool down to room temperature (20.0 ºC) before drinking it. Essenti
vladimir2022 [97]

Answer:

232 J/K

Explanation:

The amount of heat gained by the air = the amount of heat lost by the tea.

q_air = -q_tea

q = -mCΔT

q = -(0.250 kg) (4184 J/kg/ºC) (20.0ºC − 85.0ºC)

q = 68,000 J

The change in entropy is:

dS = dQ/T

Since the room temperature is constant (isothermal):

ΔS = ΔQ/T

Plug in values (remember to use absolute temperature):

ΔS = (68,000 J) / (293 K)

ΔS = 232 J/K

5 0
3 years ago
Use the work energy theorem to solve each of these problems and neglect air resistance in all cases. a) A branch falls from the
Sav [38]

Answer:

a)43.8 m/s

b)103.54 m/s

Explanation:

Work energy theorem

ΔE_{k}= ΔE_{g}

E_{k2} - E_{k1}=-(E_{g2} - E_{g1})\\\\ \frac{1}{2} mv^{2}_{2}- \frac{1}{2} mv^{2}_{1}+ mgh_{2} - mgh_{1} = 0

a) In this part v1=0 and h2=0

\frac{1}{2} mv^{2}_{2}- \frac{1}{2} mv^{2}_{1}+ mgh_{2}- mgh_{1} = 0\\\\\\\\\v_{2} =\sqrt{2gh_{1}} = \sqrt{2*9.8*98} =43.8 m/s=0

b) in this part v2=0, h1= 0, and h2= 545m

\frac{1}{2} v^{2}_{1}= gh_{2} \\v_{1} =\sqrt{2gh_{2}}=103.54m/s

5 0
3 years ago
A car traveled 330 miles in 6 hours. What is the average speed?
shusha [124]

it is 55 mph that is ok


6 0
3 years ago
A 60-kg runner raises his center of mass approximately 0.5 m with each step. Although his leg muscles act as a spring, recapturi
Darina [25.2K]

Answer: P = 36.75W

The additional power needed to account for the loss is 36.75W.

Explanation:

Given;

Mass of the runner m= 60 kg

Height of the centre of gravity h= 0.5m

Acceleration due to gravity g= 9.8m/s

The potential energy of the body for each step is;

P.E = mgh

P.E = 60 × 9.8 × 0.5

PE = 294J

Since the average loss per compression on the leg is 10%.

Energy loss = 10% (P.E)

E = 10% of 294J

E = 29.4J

To calculate the runner's additional power

given that time per stride is = 0.8s

Power P = Energy/time

P = E/t

P = 29.4J/0.8s

P = 36.75W

5 0
3 years ago
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