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Ymorist [56]
4 years ago
11

Q1: How are rational exponents and radicals related? Q2: How can the average rate of change be identified for a function? Q3: Ho

w do linear and exponential functions compare as the domain increases?
Mathematics
1 answer:
masha68 [24]4 years ago
8 0

Answer:

The answer is given below

Step-by-step explanation:

Q1: How are rational exponents and radicals related?

Rational exponents are exponents in fraction form. Radicals are roots (square root, cube root and so on).

The denominator of the rational exponent is the root which is the same as the radical.

Q2: How can the average rate of change be identified for a function?

The average rate of change is ratio of the change in output to the change in input values. The average rate of change for a function is the slope of the function.

It can be gotten by finding the first derivative of he function.

Q3: How do linear and exponential functions compare as the domain increases?

For linear functions as x increases, y also increases by the same amount (i.e rate of change is constant). For exponential function the rate of change increases by a factor known as the multiplier.

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Musya8 [376]

Answer:

\large \boxed{\sf \ \ \dfrac{1}{x^2}+\dfrac{1}{x^2+x}=\dfrac{2x+1}{x^2(x+1)} \ \ }

Step-by-step explanation:

Hello,

This is the same method as computing for instance:

\dfrac{1}{2}+\dfrac{1}{3}=\dfrac{3+2}{2*3}=\dfrac{5}{6}

We need to find the same denominator.

Let's do it !

For any x real different from 0, we can write:

\dfrac{1}{x^2}+\dfrac{1}{x^2+x}=\dfrac{1}{x^2}+\dfrac{1}{x(x+1)}\\\\=\dfrac{x+1+x}{x^2(x+1)}=\dfrac{2x+1}{x^2(x+1)}

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

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Dmitriy789 [7]
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6/19

Step-by-step explanation:

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Step-by-step explanation:

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