the dot plot above identifies the number of pets living with each of 20 families in an apartment building .what fraction of fami
lies have more than two pets
1 answer:
Answer:
B. ⅕
Step-by-step explanation:
Fraction of families having more than 2 pets = families with pets of 3 and above ÷ total number of families in the apartment
From the dot plot above, 3 families have 3 pets, and 1 family has 4 pets.
Number of families with more than 2 pets = 3 + 1 = 4
Fraction of families with more than 3 pets =
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I round the answer to the second digit and get 18.33
So to find the answer you have to know what the mixture is, what the trend is,
on day one he used 4 cans of blue and 6 cans of yellow
day two, 6 blue and 9 yellow
both are divisible by 2 and 3 respectively, additionally when you divide the number of blue cans Marc used by the number of yellow cans each day you get a sum of .66
those are the trends
so therefore day three would have the same trend.
Now on day three Marc will have 4 cans of blue paint and 5 cans of yellow paint remaining, what I did here to find the answer was divide numbers under 4 and 5 until I got a division problem that equaled .66
my answer was 2 blue cans and 3 yellow.
The answer is that on day three the highest number of cans that Marc can mix to get his favorite shade of green is 2 blue and 3 yellow
on day one he used 4 cans of blue and 6 cans of yellow
day two, 6 blue and 9 yellow
both are divisible by 2 and 3 respectively, additionally when you divide the number of blue cans Marc used by the number of yellow cans each day you get a sum of .66
those are the trends
so therefore day three would have the same trend.
Now on day three Marc will have 4 cans of blue paint and 5 cans of yellow paint remaining, what I did here to find the answer was divide numbers under 4 and 5 until I got a division problem that equaled .66
my answer was 2 blue cans and 3 yellow.
The answer is that on day three the highest number of cans that Marc can mix to get his favorite shade of green is 2 blue and 3 yellow
Answer:
Dimension of the box is
The volume of the box is 280.05 in³.
Step-by-step explanation:
Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.
To find : The dimensions and the volume of the box?
Solution :
Let h be the height of the box which is the side length of a corner square.
According to question,
A sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.
The length of the box is
The width of the box is
The volume of the box is
To maximize the volume we find derivative of volume and put it to zero.
Solving by quadratic formula,
Now, substitute the value of h in the volume,
When, h=2.45
When, h=8.54
Rejecting the negative volume as it is not possible.
Therefore, The volume of the box is 280.05 in³.
The dimension of the box is
The height of the box is h=2.45
The length of the box is
The width of the box is
So, Dimension of the box is