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Vilka [71]
3 years ago
8

Vanessa throws a tennis ball in the air. the function h(t) = -16t2 + 45t + 7 represents the distance, in feet, that the ball is

from the ground at any time t. at what time, to the nearest tenth of a second, is the ball at its maximum height? t = seconds listen submit answer previous next
Mathematics
1 answer:
antiseptic1488 [7]3 years ago
4 0
Given that height, h(t) of a tennis ball is modeled by the equation h(t)=<span>-16t^2 + 45t + 7, the time taken for the ball to reach maximum height will found as follows:
at maximum height:
h'(t)=0
but from the equation:
h'(t)=-32t+45=0
solving for t we get
t=45/32
t=1.40625~1.4 seconds
Thus the time taken to reach maximum height is 1.4 seconds


</span>
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Slope = rise/run = 10/50 = 1/5
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D’Andra has a dentist appointment in 5 weeks. There are 7 days in a week. How many days are in 5 weeks?
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Answer:

A. 35

Step-by-step explanation:

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Thus, the answer is A.

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At what rate percent will the interest on Rs. 6300 in 10 years be equal to its principal?​
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6 0
3 years ago
Use the factors of the function and the y-intercept to find the standard form of the equation representing Jared’s function. Typ
Georgia [21]

The y-intercept of a function is the point where the graph crosses the \mathbf{y = x^3 + 2x^2 - 193x - 270 }

  • The factors of the Jared's graph are: (x - 10), (x + 3) and (x + 9)
  • The y-intercept is -13.5
  • The standard equation of the function is: \mathbf{y = x^3 + 2x^2 - 193x - 270 }

<u>(a) The factors</u>

First, we write out the points where the function cross the x-axis.

The points are:

\mathbf{x = 10}

\mathbf{x = -3}

\mathbf{x = -9}

Equate the above points to 0

\mathbf{x -10 = 0}

\mathbf{x +3 = 0}

\mathbf{x +9 = 0}

Hence, the factors are: (x - 10), (x + 3) and (x + 9)

<u>(b) The y-intercept</u>

This is the point where the graph crosses the y-axis.

From the attached graph, the graph crosses the y-axis at -13.5.

Hence, the y-intercept is -13.5

<u>(c) The standard form</u>

In (a), we have:

\mathbf{x -10 = 0}

\mathbf{x +3 = 0}

\mathbf{x +9 = 0}

Multiply the above equations

\mathbf{(x - 10) \times (x + 3) \times (x + 9) = 0 \times 0 \times 0}

\mathbf{(x - 10) \times (x + 3) \times (x + 9) = 0 }

Expand

\mathbf{(x - 10) \times (x^2 + 3x + 9x + 27) = 0 }

\mathbf{(x - 10) \times (x^2 + 12x + 27) = 0 }

Expand

\mathbf{x^3 + 12x^2 + 27x - 10x^2 - 220x - 270 = 0 }

Collect like terms

\mathbf{x^3 + 12x^2 - 10x^2+ 27x  - 220x - 270 = 0 }

\mathbf{x^3 + 2x^2 - 193x - 270 = 0 }

Replace 0 with y

\mathbf{y = x^3 + 2x^2 - 193x - 270 }

Hence, the standard form is: \mathbf{y = x^3 + 2x^2 - 193x - 270 }

Read more about graphs and functions at:

brainly.com/question/18806107

3 0
2 years ago
Please help!! It's extra credit work, I'm on Spring break, and I'm tring to be on honor roll!!
Reika [66]

Answer: C

Explanation:

Since tan(H) equals 1, we can conclude that angle H equals 45 degrees. Therefore, we know that it is a 45-45-90 triangle. Therefore, since both legs are equal, sin or cos doesn’t matter. Therefore, C is correct. (Draw it for yourself, it helps)

8 0
3 years ago
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