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Vilka [71]
3 years ago
8

Vanessa throws a tennis ball in the air. the function h(t) = -16t2 + 45t + 7 represents the distance, in feet, that the ball is

from the ground at any time t. at what time, to the nearest tenth of a second, is the ball at its maximum height? t = seconds listen submit answer previous next
Mathematics
1 answer:
antiseptic1488 [7]3 years ago
4 0
Given that height, h(t) of a tennis ball is modeled by the equation h(t)=<span>-16t^2 + 45t + 7, the time taken for the ball to reach maximum height will found as follows:
at maximum height:
h'(t)=0
but from the equation:
h'(t)=-32t+45=0
solving for t we get
t=45/32
t=1.40625~1.4 seconds
Thus the time taken to reach maximum height is 1.4 seconds


</span>
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Please help me complete this !! 12points
Svet_ta [14]

Answer:

1.

x1=1

x2=3

y1=5

y2=1

midpoint= (x1+x2/2, y1+y2/2)=(1+3/2,5+1/2)=(2,3)

2.

x1=2

x2=4

y1=4

y2=6

midpoint= (x1+x2/2, y1+y2/2)=(2+4/2,4+6/2)=(3,5)

3.

x1= -2

x2=4

y1=4

y2= -6

midpoint= (x1+x2/2, y1+y2/2)=(-2+4/2,4-6/2)=(1,-1)

4.

x1=0

x2=0

y1=3

y2=5

midpoint= (x1+x2/2, y1+y2/2)=(0/2,3+5/2)=(0,4)

5.

x1= -2

x2=2

y1= -6

y2=6

midpoint= (x1+x2/2, y1+y2/2)=(-2+2/2,-6+6/2)=(0,0)

6.

x1=1

x2=4

y1=4

y2=5

midpoint= (x1+x2/2, y1+y2/2)=(1+4/2,4+5/2)=(5/2,9/2)

7.

x1=-3

x2=-4

y1=5

y2=5

midpoint= (x1+x2/2, y1+y2/2)=(-3-4/2,5+5/2)=(-7/2,5)

8.

x1=5

x2= -4

y1=2

y2=6

midpoint= (x1+x2/2, y1+y2/2)=(5-4/2,2+6/2)=(1/2,4)

3 0
2 years ago
What is the solution to 5(3-x)?
Anit [1.1K]
The answer is 15 - 5 x

Multiply 5 by 3 ( 15 )
Multiply 5 by -x ( -5x )

I hope this helps and please mark brainliest!
8 0
2 years ago
G(x)=3^x +1 and f(x)=3x+1 which values of x makes f(x) =g(x) true
fomenos

Answer:

x=1

Step-by-step explanation:

3^x +1

f(x)=3x+1

f(x) =g(x)

3x +1 =3^x +1

Subtract 1 from each side

3x = 3^x

Let x =1

3*1 = 3^1

3=3

5 0
3 years ago
Read 2 more answers
If you know that the exact volume of a cylinder is 500 π cm3, how can you find the approximate volume, without knowing the heigh
grandymaker [24]

Answer:

The approximate volume is 1,570\ cm^{3}

Step-by-step explanation:

we know that

The exact volume of the cylinder is  

V=500\pi \ cm^{3}

so

To find the approximate volume of the cylinder, substitute the term \pi by the approximate value of  3.14 and then multiply  

so

V=500(3.14)=1,570\ cm^{3}

6 0
3 years ago
Plsss helppp I’m dying!! —&gt; Complete the square to determine if the equation is a circle, quadratic equation, or other
sashaice [31]

a) The equation represents an ellipse.

b) The equation represents a circle.

c) The equation represents a parabola.

<h3>How to infer the graphical form of a general equation</h3>

In this problem we have <em>general</em> equations of the form A · x² + B · y² + C · x + D · y + E = 0, which have to be modified into <em>standard</em> form to infer its <em>graphical</em> form. This procedure can be done by <em>algebra</em> properties:

16 · x² + 4 · y² + 96 · x - 8 · y + 84 = 0

[(4 · x)² + 2 · 12 · (4 · x)] + [(2 · y)² - 2 · 2 · (2 · y)] = - 84

[(4 · x)² + 2 · 12 · (4 · x) + 144] + [(2 · y)² - 2 · 2 · (2 · y) + 4] = 64

(4 · x + 12)² + (2 · y + 2)² = 64

4² · (x + 3)² + 2² · (y + 2)² = 64

(x + 3)² / 4 + (y + 2)² / 16 = 1 : Ellipse

x² + y² + 8 · x - 6 · y - 15 = 0

(x² + 8 · x) + (y² - 6 · y) = 15

(x² + 2 · 4 · x + 16) + (y² - 2 · 3 · y + 9) = 40

(x + 4)² + (y - 3)² = 40 : Circle

x² + 6 · x + 4 · y + 5 = 0

x² + 6 · x + 5 = - 4 · y

y = - (1 / 4) · x² - (3 / 2) · x - (5 / 4) : Parabola

To learn more on ellipses: brainly.com/question/19507943

#SPJ1

4 0
1 year ago
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