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vitfil [10]
3 years ago
7

wants the perimeter of his rectangular garden to be, at most, 60 feet. He plans on making the length 19 feet. what is the maximu

m width of his garden , Solving Equations Word problems geometry and angles
Mathematics
1 answer:
Elina [12.6K]3 years ago
3 0

Answer:

width = 11 feet

Step-by-step explanation:

The perimeter of a rectangle is 2 times length + width.

He already decided that the perimeter is at most 60 feet and the length is 19 feet. Then replacing in the formula for perimeter you have:

60 = 2 ( 19 + width)

30 = 19 + width

11 = width

Therefore the maximum width is 11 feet

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Karen had 2 spools of wire. Each spool had 15 7/8 yards of wire. Karen used 3 yards of wire from each spool. How many yards of w
Anna11 [10]

You'd have 25 6/8 yards of wire left because she took 3 yards from each spool. So that gives us 2 spools of 12 7/8 and when you add them you get 25 6/8.

7 0
3 years ago
Read 2 more answers
Find the real numbers x and y if -3+ix^2y and x^2+y+4i are conjugate of each other. Pls solve with the steps
Firdavs [7]
ANSWER
x = ±1 and y = -4.
Either x = +1 or x = -1 will work

EXPLANATION
If -3 + ix²y and x² + y + 4i are complex conjugates, then one of them can be written in the form a + bi and the other in the form a - bi. In other words, between conjugates, the imaginary parts are same in absolute value but different in sign (b and -b). The real parts are the same

For -3 + ix²y
⇒ real part: -3
⇒ imaginary part: x²y

For x² + y + 4i
⇒ real part: x² + y (since x, y are real numbers)
⇒ imaginary part: 4

Therefore, for the two expressions to be conjugates, we must satisfy the two conditions. 

Condition 1: Imaginary parts are same in absolute value but different in sign. We can set the imaginary part of -3 + ix²y to be the negative imaginary part of x² + y + 4i so that the 

   x²y = -4 ... (I)

Condition 2: Real parts are the same

   x² + y = -3 ... (II)

We have a system of equations since both conditions must be satisfied

   x²y = -4 ... (I)
   x² + y = -3 ... (II)

We can rearrange equation (II) so that we have

   y = -3 - x² ... (II)

Substituting into equation (I)

   x²y = -4 ... (I)
   x²(-3 - x²) = -4
   -3x² - x⁴ = -4
   x⁴ + 3x² - 4 = 0
   (x² + 4)(x² - 1) = 0
   (x² + 4)(x-1)(x+1) = 0

Therefore, x = ±1.
Leave alone (x² + 4) as it gives no real solutions.

Solve for y:

   y = -3 - x² ... (II)
   y = -3 - (±1)²
   y = -3 - 1
   y = -4

So x = ±1 and y = -4. We can confirm this results in conjugates by substituting into the expressions:

   -3 + ix²y 
   = -3 + i(±1)²(-4)
   = -3 - 4i

   x² + y + 4i
   = (±1)² - 4 + 4i
   = 1 - 4 + 4i
   = -3 + 4i

They result in conjugates
4 0
3 years ago
Read 2 more answers
True or false just answer like that pls
sveta [45]

Answer:

false

false

true

false

true

Step-by-step explanation:

brainliest?

3 0
2 years ago
(01.04)
Ymorist [56]

Answer:2

Step-by-step explanation: the equation is in linear form y=mx+b, the b represents the y intercept in your equation that would be -5

5 0
3 years ago
Tell which number is greater.<br><br> 1/3, 30%
Olin [163]
Mhm pretty sure 1/3
8 0
3 years ago
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