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3 years ago

How to solve the second equation

Mathematics

1 answer:

ivann1987 [24]3 years ago

4 0

$\bf \textit{ vertex of a vertical parabola, using coefficients}\\\\
\begin{array}{lccclll}
y = &{{ -0.02}}x^2&{{ +1}}x&{{ +6}}\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}\qquad 
\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)
\\\\\\
\left( -\cfrac{1^2}{2(-0.02)}~~,~~6-\cfrac{1^2}{4(-0.02)} \right)
\\\\\\
(\stackrel{\textit{how far ahead it went}}{25}~,~\stackrel{\textit{how high it went}}{18\frac{1}{2}})$

$\bf \textit{ vertex of a vertical parabola, using coefficients}\\\\
\begin{array}{lccclll}
y = &{{ -0.01}}x^2&{{ +0.7}}x&{{ +6}}\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}\qquad 
\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)
\\\\\\
\left( -\cfrac{0.7^2}{2(-0.01)}~~,~~6-\cfrac{0.7^2}{4(-0.01)} \right)
\\\\\\
(\stackrel{\textit{how far ahead it went}}{24\frac{1}{2}}~,~\stackrel{\textit{how high it went}}{18\frac{1}{2}})$

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Help me please :>>>>>>>

Ket [755]

Answer:

C. Median

Step-by-step explanation:

If both sides are <em>symmetrical,</em> then there is no need to try and find the mean or anything because you already have the middle point and no outliers. <u>If there were outliers it'd be different</u>, unless the outliers were symmetrical with the rest of it, then the median would still be a good option.

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2 years ago

Read 2 more answers

I’m so bad at this ughhhhhhhhhhhhhhhhhhh

Alexus [3.1K]

Answer:

a)6

b)v^2-u^2/2a

Step-by-step explanation:

a)Given that,

u=12

a= -6

s=9

We know that,

v^2=u^2+2as

or, v^2=(12)^2+2×(-6)×9

or,v^2=144-108

or,v^2=36

or, v=√36

∴v=6

(Ans)

b)If ,v^2=u^2+2as

then, u^2+2as=v^2

or,2as=v^2-u^2

or, s=v^2-u^2/2a

∴s=v^2-u^2/2a

Hope ya find it helpful.. Thanks a lot...

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3 years ago

Which equation is true?

enot [183]

Lets solve all of these:-

#1

√361 = 361 · 2

?
√361 = 361 · 2
√361 = 19
361 · 2 = 722

19 ≠ 722
So this equation is not true

#2:-

√361 = 19²

?
√361 = 19²
√361= 19
19² = 19 · 19 = 361

19 ≠ 361
So this equation is not true

√361 = 361 ÷ 2

?
√361 = 361 ÷ 2
√361 = 19
361 ÷ 2 = 180.5

√361 ≠ 361 ÷ 2
So this equation is not true

√361 = √19²
√361 = 19
√19² = 19

19 = 19

SO the last one is right. Hope I helped ya!! xD

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3 years ago

Write the next whole number after 4444 in the base-five system.

svet-max [94.6K]

<h3>Answer: 10000 in base 5</h3>

====================================================

Explanation:

4+1 = 5 in base 10

But in base 5, the digit "5" does not exist.

The only digits in base five are: 0, 1, 2, 3, 4

This is similar to how in base ten, the digits span from 0 to 9 with the digit "10" not being a thing (rather it's the combination of the digits "1" and "0" put together).

----------------

Anyways let's go back to base 5.

Instead of writing 4+1 = 5, we'd write 4+1 = 10 in base 5. The first digit rolls back to a 0 and we involve a second digit of 1.

Think how 9+1 = 10 in base 10.

Similarly,

44+1 = 100 in base 5

444+1 = 1000 in base 5

4444+1 = 10000 in base 5

and so on.

----------------

Here are the first few numbers in base 5, when counting up by 1 each time.

0, 1, 2, 3, 4,

10, 11, 12, 13, 14,

20, 21, 22, 23, 24,

30, 31, 32, 33, 34,

40, 41, 42, 43, 44,

100, 101, 102, 103, ...

Notice each new row is when the pattern changes from what someone would expect in base 10. This is solely because the digit "5" isn't available in base 5.

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2 years ago

Find the first four terms of the recursive sequence defined by the following formula: an = an-1 4 where a4 = 2 1 4 , , , 2 1 4.

Elina [12.6K]

The first four-term of the sequence is found by the given equation $a_{n-1} = 4a_n$ is given as 144, 36, 9, and 9/4.