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Kaylis [27]
3 years ago
14

If 1 foot 12 inches, which expression can be used to find the

Mathematics
2 answers:
Liono4ka [1.6K]3 years ago
7 0
B is the right awnser
kvv77 [185]3 years ago
4 0
B. please make me branelist
You might be interested in
In an arithmetic series, what is the sum of the first 22 terms if the first term is 12 and the common difference is 3?
Vilka [71]

Answer:

561

Step-by-step explanation:

an = dn - (a-d)

The difference is 3.

The first term is 12.

an = 3n - (12-3)

an = 3n - 9

Put n as 1, 2, 3, 4, 5 ....22.

3(1) - 9 = -6

3(2) - 9 = -3

3(3) - 9 = 0

3(4) - 9 = 3

3(5) - 9 = 6

...

3(22) - 9 = 57

Add the first 22 terms.

-6+-3+0+3+6+9+12+15+18+21+24+27+30+33+36+39+42+45+48+51+54+57

= 561

4 0
3 years ago
75% OFF!
ICE Princess25 [194]
$676.

If the sale price of the coat is $169, you are looking for the original price. I like to think about it in the sense that if an item is 75% off, you are paying 25% of the original amount. Using that logic, in order to determine the sale price you would use the equation

Original price * 25% = $169

To solve for the original price:

Original price = $169/.25 = $676.
7 0
3 years ago
3 equivalent ratios for 1/10
nataly862011 [7]

Answer:

So just as a fraction of 3/30 can be simplified to 1/10, a ratio of 3:30 (or 4:40, 5:50, 6:60 and so on) can be simplified to 1:10.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What is 23 % changed into a fraction
MaRussiya [10]
23% as a fraction would be 23/100
7 0
3 years ago
Read 2 more answers
A movie theater has a seating capacity of 329. The theater charges $5.00 for children, $7.00 for students, and $12.00 of adults.
kipiarov [429]

Answer:

170 children

74 students

85 adults

Step-by-step explanation:

Given

Let:

C = Children; S = Students; A = Adults

For the capacity, we have:

C + S + A = 329

For the tickets sold, we have:

5C + 7S + 12A = 2388

Half as many as adults are children implies that:

A = \frac{C}{2}

Required

Solve for A, C and S

The equations to solve are:

C + S + A = 329 -- (1)

5C + 7S + 12A = 2388 -- (2)

A = \frac{C}{2} -- (3)

Make C the subject in (3)

C = 2A

Substitute C = 2A in (1) and (2)

C + S + A = 329 -- (1)

2A + S + A = 329

3A + S = 329

Make S the subject

S = 329 - 3A

5C + 7S + 12A = 2388 -- (2)

5*2A + 7S + 12A = 2388

10A + 7S + 12A = 2388

7S + 22A = 2388

Substitute S = 329 - 3A

7(329 - 3A) + 22A = 2388

2303 - 21A + 22A = 2388

2303 +A = 2388

Solve for A

A = 2388 - 2303

A = 85

Recall that: C = 2A

C = 2 * 85

C = 170

Recall that: S = 329 - 3A

S = 329 - 3 * 85

S = 329 - 255

S = 74

Hence, the result is:

C = 170

S = 74

A = 85

8 0
3 years ago
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