Question

George tells you that when variables are in the denominator, the equation becomes unsolvable. "There is a value for x that makes the denominator zero, and you can't divide by zero," George explains. Using complete sentences, demonstrate to George how the equation is still solvable.

Answer 1

The equation can still be solved but it should be stated clearly at what value of would the equation be undefined. For instance, you have an expression,

1/x+2

When x is equal to -2, the denominator will be 0 resulting to an undefined solution. The value of x here can be any real number except -2.