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2 years ago

3/5x+19−3/20x−7/35x+19−3/20x−7 simplified is

2 answers:

8 0

3/5x + 19 - 3/20x - 7/35x + 19 - 3/20x - 7
84/140x + 19 - 21/140x - 28/140x + 19 - 21/140x - 7 =
84/140x - 70/140x + 38 - 7
14/140x + 31 =
1/10x + 31 <==

dalvyx [7]2 years ago

5 0

Hello,
3/5x+19−3/20x−7/35x+19−3/20x−7;
(3/5-3/20-7/35-3/20)x+(19+19-7);
(3/5-3/20-1/5-3/20)x+31;
(12-3-4-3/20)+31;
2/20x+31;
1/10x+31;

Bye :-)

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Transform the given quadratic function into vertex form f(x) = quadratic function into vertex form f(x) = quadratic function int

vesna_86 [32]

Answer:

$f(x) = 3(x -\frac{2}{3})^2 -\frac{22}{3}$

The vertex is $(\frac{2}{3}, -\frac{22}{3})$

Step-by-step explanation:

For a general quadratic function the form is:

$ax ^ 2 + bx + c$

For the function

$f(x) = 3x ^ 2 -4x -6$

Take common factor 3.

$f(x) = 3(x ^ 2 -\frac{4}{3}x - 2)$

The values of the coefficients for the function within the parenthesis are the following: $a = 1$ , $b = -\frac{4}{3}$ , $c = -2$

Take the value of b and divide it by 2. Then, the result obtained squares it.

$\frac{b}{2}= -\frac{2}{3}$

$(\frac{b}{2})^2=\frac{4}{9}$

Add and subtract $\frac{4}{9}$

$f(x) = 3([x ^ 2 -\frac{4}{3}x +\frac{4}{9}]- 2-\frac{4}{9})$

Write the expression of the form

$f(x) = (x-\frac{b}{2})^2 +k$

$f(x) = 3(x -\frac{2}{3})^2 -\frac{22}{3}$

The vertex is $(\frac{2}{3}, -\frac{22}{3})$

3 0

2 years ago

What is the relative error of a distance given as 550cm plus or minus 24.2cm?

AnnyKZ [126]

24.2 / 550 = 0.044

The relative error is plus or minus 4.4 percent .

5 0

3 years ago

Read 2 more answers

Plz help w this math problem

Svetllana [295]

Answer:

• for x = 2a√t, make t the subject:

${ \tt{x = 2a \sqrt{t} }} \\ \\ { \tt{ \sqrt{t} = \frac{x}{2a} }} \\ \\ { \boxed{ \tt{t = \frac{ {x}^{2} }{4 {a}^{2} } }}}$

• then find y:

${ \tt{y = {ar}^{2} - 2at}} \\ \\ { \tt{y = {ar}^{2} - 2a( \frac{ {x}^{2} }{4 {a}^{2} } ) }} \\ \\ { \boxed{ \tt{y = {ar}^{2} - \frac{ {x}^{2} }{2a} }}}$