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3 years ago

Read the problem and decide whether it has too much or too little

Mathematics

1 answer:

Arte-miy333 [17]3 years ago

4 0

Answer:

A. too much

Step-by-step explanation:

If we are only looking for how much water she drinks, we do not need to know the amount of hay or the amount of fruit

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Factor completely: 4x2 + 25x + 6

IceJOKER [234]

(x + 6)(4x + 1)
x times 4x = 4x^2
x times 1 = x
6 times 4x = 24x
6 times 1 = 6
And finally, by adding like terms, 4x^2 + 25x + 6

I hope this helps you! Good luck :)

7 0

3 years ago

Select the correct answer,

Bad White [126]

Answer:

Step-by-step explanation:

liquidity risk. because the shorter the term the lesser the liquidity.

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2 years ago

Please, help!!!!! ASAP!!! It's triangle JKL.

Wewaii [24]

Answer:

Step-by-step explanation:

first look at all the equation and solve them. When you get the all of there answer then divide the answers by the sides. And then you will find your answer!

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3 years ago

For question 25 please pick 1,2,3 or 4

Juli2301 [7.4K]

Answer:

$x=\frac{2}{3} \pm \frac{1}{6}i \sqrt{158}$

Step-by-step explanation:

$18x^2-24x+87=0$

Using Quadratic Formula

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{-\left(-24\right)\pm \sqrt{\left(-24\right)^2-4\cdot \:18\cdot \:87}}{2\cdot \:18}$

Solving the discriminant:

$\Delta = \left(-24\right)^2-4\cdot \:18\cdot \:87\\\Delta = 576-6264\\ \Delta=-5688$

$x= \frac{24 \pm \sqrt{-5688} }{36}$

$x= \frac{24 \pm \sqrt{5688i} }{36}$

Once $\sqrt{5688} =\sqrt{2^3\cdot \:3^2\cdot \:79}=6\sqrt{158}$

$x=\frac{24\pm6\sqrt{158}i}{36}$

Dividing the denominator and numerator by 6

$x=\frac{4\pm \sqrt{158}i}{6}$

Now rewrite it:

$x=\frac{4}{6} \pm i\frac{\sqrt{158}}{6}$

$x=\frac{2}{3} \pm i \frac{\sqrt{158}}{6}$

$x=\frac{2}{3} \pm \frac{1}{6}i \sqrt{158}$

5 0

3 years ago

evaluate the fermi function for an energy KT above the fermi energy. find the temperature at which there is a 1% probability tha

dybincka [34]

Complete Question

Evaluate the Fermi function for an energy kT above the Fermi energy. Find the temperature at which there is a 1% probability that a state, with an energy 0.5 eV above the Fermi energy, will be occupied by an electron.

Answer:

The Fermi function for the energy KT is $F(E_o) = 0.2689$

The temperature is $T_k = 1261 \ K$

Step-by-step explanation:

From the question we are told that

The energy considered is $E = 0.5 eV$

Generally the Fermi function is mathematically represented as

$F(E_o) = \frac{1}{e^{\frac{[E_o - E_F]}{KT} } + 1 }$

Here K is the Boltzmann constant with value $k = 1.380649 *10^{-23} J/K$

$E_F$ is the Fermi energy

$E_o$ is the initial energy level which is mathematically represented as

$E_o = E_F + KT$

$F(E_o) = \frac{1}{e^{\frac{[[E_F + KT] - E_F]}{KT} } + 1}$

=> $F(E_o) = \frac{1}{e^{\frac{KT}{KT} } + 1}$

=> $F(E_o) = \frac{1}{e^{ 1 } + 1}$

=> $F(E_o) = 0.2689$

Generally the probability that a state, with an energy 0.5 eV above the Fermi energy, will be occupied by an electron is mathematically represented by the Fermi function as

$F(E_k) = \frac{1}{e^{\frac{[E_k - E_F]}{KT_k} } + 1 } = 0.01$