Multiply 400 times 0.70 and that’s how you get the % (in this case 280)
the parallel line is 2x+5y+15=0.
Step-by-step explanation:
ok I hope it will work
soo,
Solution
given,
given parallel line 2x+5y=15
which goes through the point (-10,1)
now,
let 2x+5y=15 be equation no.1
then the line which is parallel to the equation 1st
2 x+5y+k = 0 let it be equation no.2
now the equation no.2 passes through the point (-10,1)
or, 2x+5y+k =0
or, 2*-10+5*1+k= 0
or, -20+5+k= 0
or, -15+k= 0
or, k= 15
putting the value of k in equation no.2 we get,
or, 2x+5y+k=0
or, 2x+5y+15=0
which is a required line.
Answer:
option f is right
Step-by-step explanation:
Given that data is collected to perform the following hypothesis test.
(right tailed test)
Sample mean = 5.4
p value = 0.1034
when p value = 0.1034 we normally accept null hypothesis. i.e chances of null hypothesis true is the probability of obtaining test results at least as extreme as the results actually observed during the test, assuming that the null hypothesis is correct
f) If the mean µ does not differ significantly from 5.5 (that is, if the null hypothesis is true), then the probability of obtaining a sample mean y as far or farther from 5.5 than 5.4 is .1034.
.
Answer:
Y=1/3
Step-by-step explanation:
X=k/y
So let's make k the subject of formula
k=xy
x=1,y=5
So let's substitute
k=1×5
k=5
So we are to determine the value for y when x is 15
So let's solve
Y=k/x
Y=5/15
Y=1/3
Y=0.333333~0.3
Answer:
(-1)ⁿ(3)ⁿ/10
Step-by-step explanation:
The first term a = 0.3, the second term, ar = 0.9. The common ratio r = ar/a = 0.9/-0.3 = -3.
From the general term of a geometric series,
U = arⁿ⁻¹
= (0.3)(-3)ⁿ⁻¹
= (3/10)(-3)ⁿ⁻¹
= (-1)ⁿ⁻¹(3)(3)ⁿ⁻¹/10
= (-1)ⁿ(3)ⁿ/10
