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3 years ago

Help !! Is the work shown in the simplification below correct? Explain.

Mathematics

2 answers:

melomori [17]3 years ago

6 0

Try this solution:
1. rules:
$cosec(t)= \frac{1}{sin(t)} ; \ sec(t)= \frac{1}{cos(t)} .$
2. according to the rule described above:
$\frac{cosec(t)}{sec(t)}= \frac{1}{sin(t)}: \frac{1}{cos(t)}= \frac{1}{sin(t)}* \frac{cos(t)}{1} = \frac{cos(t)}{sin(t)}=cotang(t).$

saw5 [17]3 years ago

5 0

^^^WRONG it says explain why its wrong not correct it

the CORRECT answer would be

No, the simplification is not correct.

Cosecant is the reciprocal of sine, not cosine.

Secant is the reciprocal of cosine, not sine.

The given expression simplifies to cot(t).

The identical answer, you are welcome!

Hope this helps, if so give me a thanks please!!!!

You might be interested in

Solve for y: 10.3 = 0.6y

Mademuasel [1]

Y is being multiplied by 0.6 so you have to divide by 0.6 on both sides to leave y alone.
y=10.3/0.6

7 0

3 years ago

Read 2 more answers

Can you explain how to do this math problem?

d1i1m1o1n [39]

Since the problem is 2x^2-5xy-y^3 we first have to plug in what the x and y stands for, once you do that your problem should look like this:

2(-3)^2- 5(-3)(-2)- (-2)^3

Now take the parentheses away and when you do that your signs change.

2x3^2-5x(-3)x(-2)-(-2)^3

do it again with -5x(-3)x(-2)

2x3^2-30-(-2)^3

now do this with (-2)^3

2x3^2-30-(-8)

Now evaluate the power

3^2 becomes 9

2x9-30-(-8)

then change -(-8) to a positive since two negatives make a positive

2x9-30+8

Now multiply the numbers 2x9

18-30+8

Then do 18-30 which equals -12 then add 8

Now you are left with your answer:

-4

Hope this helps! :3

6 0

3 years ago

If p(x) = x 2 + 7x + 3 is divided by x + 4, the remainder is

igor_vitrenko [27]

tep 1 : 3 Simplify — x Equation at the end of step 1 : 3 px - ((9x + —) + 4) = 0 x Step 2 :Rewriting the whole as an Equivalent Fraction :

2.1 Adding a fraction to a whole

Rewrite the whole as a fraction using x as the denominator :

9x 9x • x 9x = —— = —————— 1 x

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

2.2 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

9x • x + 3 9x2 + 3 —————————— = ——————— x x Equation at the end of step 2 : (9x2 + 3) px - (————————— + 4) = 0 x Step 3 :Rewriting the whole as an Equivalent Fraction :

3.1 Adding a whole to a fraction

Rewrite the whole as a fraction using x as the denominator :

4 4 • x 4 = — = ————— 1 x Step 4 :Pulling out like terms :

4.1 Pull out like factors :

 9x2 + 3 = 3 • (3x2 + 1)

Polynomial Roots Calculator :

4.2 Find roots (zeroes) of : F(x) = 3x2 + 1
Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient

In this case, the Leading Coefficient is 3 and the Trailing Constant is 1.

The factor(s) are:

of the Leading Coefficient : 1,3
of the Trailing Constant : 1

Let us test ....

P Q P/Q F(P/Q) Divisor -1 1 -1.00 4.00 -1 3 -0.33 1.33 1 1 1.00 4.00 1 3 0.33 1.33

Polynomial Roots Calculator found no rational roots

Adding fractions that have a common denominator :

4.3 Adding up the two equivalent fractions

3 • (3x2+1) + 4 • x 9x2 + 4x + 3 ——————————————————— = ———————————— x x Equation at the end of step 4 : (9x2 + 4x + 3) px - —————————————— = 0 x Step 5 :Rewriting the whole as an Equivalent Fraction :

5.1 Subtracting a fraction from a whole

Rewrite the whole as a fraction using x as the denominator :

px px • x px = —— = —————— 1 x Trying to factor by splitting the middle term

5.2 Factoring 9x2 + 4x + 3

The first term is, 9x2 its coefficient is 9 .
The middle term is, +4x its coefficient is 4 .
The last term, "the constant", is +3 

Step-1 : Multiply the coefficient of the first term by the constant 9 • 3 = 27

Step-2 : Find two factors of 27 whose sum equals the coefficient of the middle term, which is 4 .

-27 + -1 = -28 -9 + -3 = -12 -3 + -9 = -12 -1 + -27 = -28 1 + 27 = 28 3 + 9 = 12 9 + 3 = 12 27 + 1 = 28

Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored

Adding fractions that have a common denominator :

5.3 Adding up the two equivalent fractions

px • x - ((9x2+4x+3)) px2 - 9x2 - 4x - 3 ————————————————————— = —————————————————— x x Equation at the end of step 5 : px2 - 9x2 - 4x - 3 —————————————————— = 0 x Step 6 :When a fraction equals zero : 6.1 When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

px2-9x2-4x-3 ———————————— • x = 0 • x x

Now, on the left hand side, the x cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :
 px2-9x2-4x-3 = 0

Solving a Single Variable Equation :

6.2 Solve px2-9x2-4x-3 = 0

In this type of equations, having more than one variable (unknown), you have to specify for which variable you want the equation solved.

6 0

3 years ago

A system for tracking ships indicated that a ship lies on a hyperbolic path described by 5x2 - y2 = 20. the process is repeated

malfutka [58]

Answer:
The ship is located at (3,5)

Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III

Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II

To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.

Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = ± √9

We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3

Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5

Based on the above, the position of the ship is (3,5).

Hope this helps :)

7 0

3 years ago

GIVING BRAINLIEST!!!!

mr Goodwill [35]

Answer:

Two

Step-by-step explanation:

there is TWO sulotions!!!

4 0

3 years ago