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soldi70 [24.7K]
3 years ago
7

Simplify 3m + 7 – 4m + 6

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
4 0
Subtract or add like terms depending on the sign

3m-4m=-1m
7+6=13
Answer:
-1m+13
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PLEASE HELP!! DUE SOON!!
ryzh [129]

Answer:

Do you still need help??

Step-by-step explanation:

5 0
3 years ago
Suppose I ask you to pick any four cards at random from a deck of 52, without replacement, and bet you one dollar that at least
Tatiana [17]

Answer:

a) No, because you have only 33.8% of chances of winning the bet.

b) No, because you have only 44.7% of chances of winning the bet.

Step-by-step explanation:

a) Of the total amount of cards (n=52 cards) there are 12 face cards (3 face cards: Jack, Queen, or King for everyone of the 4 suits: clubs, diamonds, hearts and spades).

The probabiility of losing this bet is the sum of:

- The probability of having a face card in the first turn

- The probability of having a face card in the second turn, having a non-face card in the first turn.

- The probability of having a face card in the third turn, having a non-face card in the previous turns.

- The probability of having a face card in the fourth turn, having a non-face card in the previous turns.

<u><em>1) The probability of having a face card in the first turn</em></u>

In this case, the chances are 12 in 52:

P_1=P(face\, card)=12/52=0.231

<u><em>2) The probability of having a face card in the second turn, having a non-face card in the first turn.</em></u>

In this case, first we have to get a non-face card (there are 40 in the dech of 52), and then, with the rest of the cards (there are 51 left now), getting a face card:

P_2=P(non\,face\,card)*P(face\,card)=(40/52)*(12/51)=0.769*0.235=0.181

<u><em>3) The probability of having a face card in the third turn, having a non-face card in the first and second turn.</em></u>

In this case, first we have to get two consecutive non-face card, and then, with the rest of the cards, getting a face card:

P_3=(40/52)*(39/51)*(12/50)\\\\P_3=0.769*0.765*0.240=0.141

<u><em>4) The probability of having a face card in the fourth turn, having a non-face card in the previous turns.</em></u>

In this case, first we have to get three consecutive non-face card, and then, with the rest of the cards, getting a face card:

P_4=(40/52)*(39/51)*(38/50)*(12/49)\\\\P_4=0.769*0.765*0.76*0.245=0.109

With these four probabilities we can calculate the probability of losing this bet:

P=P_1+P_2+P_3+P_4=0.231+0.181+0.141+0.109=0.662

The probability of losing is 66.2%, which is the same as saying you have (1-0.662)=0.338 or 33.8% of winning chances. Losing is more probable than winning, so you should not take the bet.

b) If the bet involves 3 cards, the only difference with a) is that there is no probability of getting the face card in the fourth turn.

We can calculate the probability of losing as the sum of the first probabilities already calculated:

P=P_1+P_2+P_3=0.231+0.181+0.141=0.553

There is 55.3% of losing (or 44.7% of winning), so it is still not convenient to bet.

5 0
4 years ago
What is the value for x
Sloan [31]
Because this is a right angle triangle, we can use the Pythagorean theorem to find the missing leg.

The Pythagorean theorem is this: a^{2} + b^{2} = c^{2}

The Pythagorean theorem tells us if you square both the legs then add them up together, you will get the length of the hypotenuse squared.

We know one leg is 24 and the hypotenuse is 26. Plug them into the equation.

24^2 + b^2 = 26^2

Solve for b.

24^2 + b^2 = 26^2
576 + b^2 = 26^2
576 + b^2 = 676
b^2 = 100

Take the square root of both sides.

b = 10

So, the other leg of the triangle is 10 units long.
8 0
3 years ago
Read 2 more answers
The slope-intercept equation of a line is y= -7x-2. What are the slope and y-intercept of the line?
Naddik [55]
Slope is -7 and the y-intercept is -2
5 0
4 years ago
What does 4 3/10 equal
Dmitriy789 [7]
Using your talking about putting it into an improper fraction. it would be 43/10.
7 0
3 years ago
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