Quadrant 2 or 4. All points in quadrant 1 are both positive, all points in quadrant 3 are both negative.
Hello there!
3x - y = 3
-x + y = 3
We need to solve 3x - y = 3 for y
Let start by adding -3x to both sides
3x - y = 3
3x - 3x - y = 3 - 3x
-y = 3 - 3x
We cannot leave the variable with a negative sign. We must multiply both sides by -1
-y * -1= (3 - 3x)-1
y = 3x - 3
Substitute 3x -3 for y in -x+y=3
-x + y = 3
-x + 3x - 3 = 3
2x - 3 = 3
2x = 3 + 3
2x = 6
x = 6/2
x = 3
Now substitute 3 for x in y=3x -3
y = 3x - 3
y = 3(3) - 3
y= 9 - 3
y= 6
Thus,
The answer is x=3 and y=6
It is always my pleasure to help students like you :)
As always, I am here to help!
D) attached is a picture, I would’ve typed it out but I can’t use the square root symbol
Answer:
irrational
Step-by-step explanation:
3/4 + sqrt(2)
3/4 is rational
sqrt(2) is irrational
The sum of a rational and an irrational number is irrational
