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Free_Kalibri [48]
3 years ago
7

Please solve the question.

Mathematics
1 answer:
Brrunno [24]3 years ago
7 0

Answer:

a = 125°, b = 20°, c = 35°, d = 90°, e = 55°

Step-by-step explanation:

Quadrilateral PQRS is inscribed in a circle, therefore it is a cyclic quadrilateral.

PQ is diameter, SR is chord and PR is transversal such that:

PQ || SR... (given)

m\angle PRQ = 90°..(\angle \: inscribed \: in\: semicircle) \\\huge \red {\boxed {\therefore d = 90°}} \\\\m\angle RPQ= m\angle PRS .. (alternate \: \angle s) \\\huge \purple {\boxed {\therefore c = 35°}} \\\\In\: \triangle PQR, \\c + d + e = 180°\\35° + 90° + e = 180°\\125° + e = 180°\\e = 180° - 125°\\\huge \orange {\boxed {\therefore e = 55°}} \\\\a + e = 180°...(opposite \:\angle 's \: of \: cyclic \: quadrilateral) \\a + 55°= 180°\\a = 180°- 55°\\\huge \blue {\boxed {a = 125°}} \\\\In\: \triangle PSR, \\a + b + 35°= 180°\\125° + b + 35° = 180°\\160° + b = 180°\\b = 180° - 160°\\\huge \pink {\boxed {b = 20°}}

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Answer:

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Step-by-step explanation:

When dividing numbers by fractions, we can simply multiply the  umber by the reciprocal of the decimal. So,

4 ÷ 1/5 = 4 × (reciprocal of 1/5)

A reciprocal of a number is the same number written under 1. aka, 1 divided by that number, which simply is flipping the numerator and denominator of a number.

So the reciprocal of 1/5 is 5/1 = 5.

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\dfrac{\mathrm d}{\mathrm dx}\bigg[6x+2y\dfrac{\mathrm dy}{\mathrm dx}\bigg]=\dfrac{\mathrm d}{\mathrm dx}\bigg[0\bigg]\implies 6+2\left(\dfrac{\mathrm dy}{\mathrm dx}\right)^2+2y\dfrac{\mathrm d^2y}{\mathrm dx^2}=0

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