Answer:
the theoretical maximum energy in kWh that can be recovered during this interval is 0.136 kWh
Explanation:
Given that;
weight of vehicle = 4000 lbs
we know that 1 kg = 2.20462
so
m = 4000 / 2.20462 = 1814.37 kg
Initial velocity 
= 60 mph = 26.8224 m/s
Final velocity 
= 30 mph = 13.4112 m/s
now we determine change in kinetic energy
Δk = 
m( ² - ² )
we substitute
Δk = ×1814.37( (26.8224)² - (13.4112)² )
Δk = × 1814.37 × 539.5808
Δk = 489500 Joules
we know that; 1 kilowatt hour = 3.6 × 10⁶ Joule
so
Δk = 489500 / 3.6 × 10⁶
Δk = 0.13597 ≈ 0.136 kWh
Therefore, the theoretical maximum energy in kWh that can be recovered during this interval is 0.136 kWh
Answer:
Mars was the Roman god of War along with an agricultural guardian. He is most closely related to the god Ares of Greek Mythology. In Roman mythology, he was second in importance to Jupiter, Rome's god of the Skies and Weather. Jupiter was the king of the Roman Pantheon, husband of the queen of gods Juno. He was also Mars' father. Unlike his Greek Counterpart, Ares who was most known for his hot headed temper and associated with hate and anger, Mars was part of the Romans <em>Archaic Triad</em>, sort of like the Big Three of Greek religion. The members of said Triad included Mars, Jupiter, and Quirinus, who had no Greek equivalent. Mars was most commonly depicted in posed of valor and strength, carrying swords or shields. He wore common Roman armor, including the plumed helmet. He was pictured as a strong leader of the Roman Army. The fourth planet from the Sun was given the name Mars when it was first discovered because it was red, much like the main color the Roman god was affiliated with.
This was mostly just random facts but i hope it helped some with your essay :)
Explanation:
It is given that,
Radius of curvature of the mirror, R = 1.54 cm
(a) We have to find the focal length of the mirror. The relationship between the focal length and the radius of curvature is given by :
f = focal length of the mirror
f = 0.77 cm
(b) The power of mirror is given by the reciprocal of focal length i.e.
Power, 
P = 1.29 diopters
Hence, this is the required solution.
Answer:
The charge passes a given point in the conductor during this time is 9.8 C.
Explanation:
Given that,
Current = 1.4 A
Time = 7.0 sec
We need to calculate the charge during this time
Charge :
Charge is the product of current and time.
In mathematically form,
Where, i = cirrent
t = time
Put the value into the formula
Hence, The charge passes a given point in the conductor during this time is 9.8 C.
