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3 years ago

5

A lightbulb has a resistance of 285 ω when operating with a potential difference of 110 v across it. what is the current in the

lightbulb?

1 answer:

Doss [256]3 years ago

5 0

Current = voltage / resistance

= 110 v / 285 Ω

= 0.386 Ampere (rounded)

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