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MissTica
3 years ago
5

A lightbulb has a resistance of 285 ω when operating with a potential difference of 110 v across it. what is the current in the

lightbulb?
Physics
1 answer:
Doss [256]3 years ago
5 0

Current = voltage / resistance

             =   110 v / 285 Ω

             =      0.386 Ampere  (rounded)
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\bar F = 12000\,N

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