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MissTica
3 years ago
5

A lightbulb has a resistance of 285 ω when operating with a potential difference of 110 v across it. what is the current in the

lightbulb?
Physics
1 answer:
Doss [256]3 years ago
5 0

Current = voltage / resistance

             =   110 v / 285 Ω

             =      0.386 Ampere  (rounded)
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<u>Explanation:</u>

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By twice the mass yet keeping the speeds unaltered, also twice the angular momentum's to the two-puck framework.  Be that as it may, we likewise double the moment of inertia. Since L=I \times \omega, the turning rate of the two-puck framework must stay unaltered.

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Answer:

Explanation:

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3 years ago
If a car travels 216 kilometers in 4 hours, calculate its speed.
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Answer:

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Answer:

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Answer:

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where the potential is

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Let us consider that all the charge of the nucleus is in the center, therefore r is the distance from this point to the proton that is approaching

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          r^2 = \frac{ 2 k  \ Ze^2}{ 2m}

with this expression we can find the closest approach distance (r)

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3 years ago
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