Final speed of the tennis ball, moving with a speed of 5. 82 m/s , has a head-on collision with a 0. 090-kg ball is 2.964 m/s.
<h3>What is conservation of momentum?</h3>
Momentum of an object is the force of speed of it in motion. Momentum of a moving body is the product of mass times velocity. By the law of conservation of momentum,
![m_1u_1 + m_2u_2 = (m_1+m_2)v](https://tex.z-dn.net/?f=m_1u_1%20%2B%20m_2u_2%20%3D%20%28m_1%2Bm_2%29v)
Here, (m) is the mass, (u) is initial velocity before collision, v is final velocity after collision and (subscript 1, and 2) are used for body 1 and 2 respectively. Rewrite the formula for final velocity as,
![v=\dfrac{m_1u_1 + m_2u_2}{(m_1+m_2)}](https://tex.z-dn.net/?f=v%3D%5Cdfrac%7Bm_1u_1%20%2B%20m_2u_2%7D%7B%28m_1%2Bm_2%29%7D)
A 0. 060-kg tennis ball, moving with a speed of 5. 82 m/s, has a head-on collision with a 0. 090-kg ball, initially moving in the same direction at a speed of 3.44 m/s. Thus, the initial velocity of the second ball is,
![v_{2f}=5.82+3.44+v_{1f}\\v_{2f}=2.38+v_{1f}](https://tex.z-dn.net/?f=v_%7B2f%7D%3D5.82%2B3.44%2Bv_%7B1f%7D%5C%5Cv_%7B2f%7D%3D2.38%2Bv_%7B1f%7D)
Let v1f is the final velocity of first ball. Thus, the initial velocity of the first ball is,
![v_{1f}=\dfrac{(0.060)(5.82) + (0.090)(3.44-2.38)}{(0.060)+(0.090)}\\v_{1f}=2.964\rm\; m/s](https://tex.z-dn.net/?f=v_%7B1f%7D%3D%5Cdfrac%7B%280.060%29%285.82%29%20%2B%20%280.090%29%283.44-2.38%29%7D%7B%280.060%29%2B%280.090%29%7D%5C%5Cv_%7B1f%7D%3D2.964%5Crm%5C%3B%20m%2Fs)
Thus, final speed of the tennis ball, moving with a speed of 5. 82 m/s , has a head-on collision with a 0. 090-kg ball is 2.964 m/s.
Learn more about the conservation of momentum here;
brainly.com/question/7538238
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